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adelina 88 [10]
2 years ago
9

Which of the following is NOT an activity used in the external environmental analysis process?a. Scanningb. Decryptingc. Monitor

ingd. Assessing
Business
1 answer:
rewona [7]2 years ago
8 0

Answer: Option B

Explanation: Studying the external factors that influence the operations of the organization is called external environment analysis.

A. Scanning in external activity refers to identifying the threats and opportunities in the environment.

C. Monitoring refers to keeping track of external factors that can affect operations.

D. Assessing involves analyzing the current trends in  various kinds of relevant factors such as political, economical etc.

.

Decrypting in simple words means decoding a data that has been saved in a code language. This is not a part of external environment analysis.  

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Mayan Company had net income of $34,000. The weighted-average common shares outstanding were 8,500. The company has no preferred
Sindrei [870]

Answer:

The company's earnings per share is $ 4.

Explanation:

EPS earning per share is an indicator widely used by investor of stock market in order to determine market value of their investment. EPS is directlty proportional to stock price.

EPS is calculated by dividing net income with outstanding common shares.

EPS = Net income/ outstanding common shares

EPS = 34,000/8,500 = $ 4

6 0
2 years ago
Read the passage. What should Jake do? What professionalism skills would he be using?
faltersainse [42]
<h2>Jake should use multi-tasking skill.</h2>

Explanation:

An employee with multi-tasking skill grows well in an organization because he can handle multiple responsibilities and that is what the need of the hour.

Jake should also prioritize the work to do multi-tasking. According to the given situation.

1. Clarify the client first. Clients are king. They bring business.

2. Make the changes in the previous report. Because this is rework and better to complete it soon.

Below are fresh works.

3. Review the report written by the co-worker

4. Write your own report.

6 0
2 years ago
Quizno's is conducting a contest in which customers are asked to name a new sandwich. The winner gets a free sandwich each day f
PIT_PIT [208]

Answer:

sales promotion

Explanation:

Sales promotions are used as a short term tactic to increase the sales of a good or service very rapidly, but they are not meant to last. Usually sales promotions offer product or monetary incentives to but the goods or services, e.g. discounts, rebates, coupons, free samples, contests, extra product, etc.

8 0
2 years ago
A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of pya, where a 5 pd2y4. if the load is kno
raketka [301]

Here is the correct question.

A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of P/A, where A= πd²/4. if the load is known with an uncertainty of ±10 percent, the diameter is known within ±5 percent (tolerances), and the stress that causes failure (strength) is known within ±15 percent, determine the minimum design factor that will guarantee that the part will not fail.

Answer:

the minimum design factor that will guarantee that the part will not fail. = 1.434

Explanation:

Looking at the uncertainty; loss of strength must be raised to \dfrac{1}{0.85} due to the stress that causes the failure (strength)  is known within ±15% uncertainty.

Looking at the uncertainty; the maximum allowable load  must be reduced to \dfrac{1}{1.1} because the load is known with an uncertainty of ±10.

Looking at the uncertainty; the diameter must be raised to \dfrac{1}{0.95}  because the diameter is known within an uncertainty of ±5.

The decrease in the maximum allowable stress can be estimated as:

\sigma' = \dfrac{P'}{A'}

where,

\sigma = stress

P = load

A = cross-sectional area of the cylinder

∴

\sigma' = \dfrac{P'}{\dfrac{\pi}{4}(d')^2}

replacing P' with \dfrac{1}{1.1}P   and d' with \dfrac{1}{0.95}d, we have:

\sigma' = \dfrac{(\dfrac{1}{1.1})\times p }{\dfrac{\pi}{4}(\dfrac{1}{0.95 } d)^2 }

\sigma' =\dfrac{P}{\dfrac{\pi}{4}d^2} (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times 0.82045

\dfrac{\sigma' }{\sigma } =0.82045

Thus, the uncertainty in diameter and the load of the allowable stress needs to decrease to 0.82045

Now, the minimum design factor that will ascertain that the part will not fail can be computed as:

n_d = \dfrac{loss  \ of  \ function \  parameter }{maximum \  allowable \ parameter}

where;

the design factor = n_d

n_d =\dfrac{\dfrac{1}{0.85} }{0.82045}

the design factor  n_d = 1.434.

Thus,  the minimum design factor that will guarantee that the part will not fail. = 1.434

7 0
2 years ago
To be competitive, ____________ recommended that American firms adopt a new management style that was a hybrid of the approaches
kakasveta [241]

Answer:

The correct answer is letter "C": William Ouchi, Theory Z.

Explanation:

American professor William Ouchi (born in 1943) proposed the "Theory Z", first described in his book "<em>Theory Z: How American Management Can Meet the Japanese Challenge</em>" which is an approach that explains how firms should develop a strong company philosophy and culture and consensus in decisions.  

Theory Z aims to employee development, as well, by concerning about their well-being, making them generalists instead of specialists, promoting individual responsibility, and monitoring them informally but with formal measures.

6 0
2 years ago
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