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jasenka [17]
2 years ago
14

A chocolate manufacturer packages chocolate bars in cardboard prisms whose bases are equilateral triangles. Each base measures 3

cm on a side. If the container is 18 cm long, how many cubic centimeters of chocolate will it hold?
Mathematics
1 answer:
Allisa [31]2 years ago
3 0

Answer:

The container will hold 70.14 cubic cm of chocolate.

Step-by-step explanation:

The base of the prisms are equilateral triangles.

Each base measures 3 cm on a side.

The length of the container = 18 cm

Area of the equilateral triangle is given by :

\frac{\sqrt{3}}{4} \times a^{2}

a = 3 so area = \frac{\sqrt{3}}{4} \times9 = 3.897 cm square

And volume will be 3.897\times18=70.14 cubic cm.

So, the container will hold 70.14 cubic cm of chocolate.

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Answer:

Sample response: Factor the GCF of five out of the total bill. Divide both terms of the expression by 5. The result is 5x – 23, which is the expression that can be used to find the amount each person pays.

i took the test.

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2 years ago
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T= 300 (d−15) 2 ​ +20space, T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, start superscript, 2,
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As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

T = \frac{(d-15)^{2}}{300}  + 20

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

As we have to find lowest average temperature, So for minimum of a function its derivative is equal to 0 there.

So lets find derivative of T function first

So first expand (d-15)^{2} as (d-15)(d-15)

we will use FOIL to multiply these

so (d-15)(d-15) = d^{2} -15d -15d +225

= d^{2} -30d +225

so we have T = \frac{d^{2} -30d +225}{300} +20

Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in dx^{2} -30d +225 we will use power rule formula:

(x^{n} )'= nx^{n-1}

so derivative of (d^{2} )'= 2d^{2-1} = 2d^{1} = 2d

Then derivative of d will be 1

so that of -30d will be -30

then derivate of constant -225 will be 0

so we will have derivative as \frac{2d-30}{300} for the fraction part and then derivative of +20 is again 0 as its constant term

T' = \frac{2d-30}{300}

For minimum we will put this derivative =0

0 = \frac{2d-30}{300}

Now solve for d

times both sides by 300

0 \times 300 = \frac{2d-30}{300} \times 300

0 = 2d-30

0 +30 = 2d -30 +30

30 = 2d

\frac{30}{2} = \frac{2d}{2}

15 = d

So now we have to find value of lowest temperature.

For that simply plug 15 in d place in original T function equation

T = \frac{(d-15)^{2}}{300}  + 20

T = \frac{(15-15)^{2}}{300}  + 20

T = 20

So T = 20 °C is the lowest average temperature and the answer.

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I am assuming that it is C. 5/4
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Answer:

The probability distribution is

X    :        0              1                 2

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Let x is the number of defective sets purchased by the hotel.

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Since there are 2 defective television sets and hotel purchase 3 sets, So, X=0,1,2.

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Hence answer is

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2 years ago
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