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dexar [7]
2 years ago
19

What are the solutions to the equation 0 = x2 – x –6? Select two options

Mathematics
2 answers:
KatRina [158]2 years ago
6 0

Answer:

x=3 or x=-2

Step-by-step explanation:

This is factorable.

The leading coefficient is 1.

Since this is a quadratic all we have to do is find two numbers that multiply to be c and add up to be b to factor the expression that is to the left of the equal sign.

By the way a quadratic expression looks like ax^2+bx+c.

So we want to find two numbers that multiply to be -6 and add up to be -1.

Those numbers are -3 and 2 since (-3)(2)=-6 and -3+2=-1.

So the factored form is:

(x-3)(x+2)=0.

Since we have a product is zero then at least one of the factors need to be zero in order for the equation to hold.

So this means we have the following two equations to solve:

x-3=0 or x+2=0

First equation we will add 3 on both sides.

Second equation we will subtract 2 on both sides.

x=3 or x=-2

Lemur [1.5K]2 years ago
5 0
(X-3)(x+2)=0

So, X=3,X= -2
X={3,-2}
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Let us say that the intersection point of lines AB and CD is called point E. The lines AB and CD are perpendicular to each other which also means that the triangle CEB is a right triangle.

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sweet-ann [11.9K]

Answer:

a) P(12.99 ≤ X ≤ 13.01) = 0.3840

b) P(X ≥ 13.01) = 0.3075

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the cental limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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\mu = 13, \sigma = 0.08

(a) Calculate P(12.99 ≤ X ≤ 13.01) when n = 16.

Here we have n = 16, s = \frac{0.08}{\sqrt{16}} = 0.02

This probability is the pvalue of Z when X = 13.01 subtracted by the pvalue of Z when X = 12.99.

X = 13.01

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{13.01 - 13}{0.02}

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Z = \frac{X - \mu}{s}

Z = \frac{12.99 - 13}{0.02}

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P(12.99 ≤ X ≤ 13.01) = 0.3840

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Z = \frac{13.01 - 13}{0.02}

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1 - 0.6915 = 0.3075

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