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2 years ago

What is the radical expression that is equivalent 27 1/5?

Mathematics

2 answers:

ollegr [7]2 years ago

8 0

For this case we have to define properties of powers and roots that:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

So, if we have the following expression:

$27 ^ {\frac {1} {5}}$

We can rewrite it as:

$\sqrt [5] {27 ^ 1} = \sqrt [5] {27}$

ANswer:

$\sqrt [5] {27}$

cestrela7 [59]2 years ago

8 0

Answer:

The required expression is $27^{\frac{1}{5} } = \sqrt[5]{27}$ or $27^{\frac{1}{5} } = \sqrt[5]{3^3}$

Step-by-step explanation:

Consider the provided expression : $27^{(\frac{1}{5} )}$

We need to find the radical expression.

Use the property:

$\sqrt[n]{x} = x^\frac{1}{n}$

Where n is the index of the radical.

By using the above property we can rewrite the above expression as:

$27^{\frac{1}{5} } = \sqrt[5]{27}$

We can write 27 = 3×3×3 = 3³

$\sqrt[5]{27} = \sqrt[5]{3^3}$

Therefore, the required expression is $27^{\frac{1}{5} } = \sqrt[5]{27}$ or $27^{\frac{1}{5} } = \sqrt[5]{3^3}$

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Find the cube roots of 27(cos 330Á + i sin 330Á). Please help c:

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Use formula
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2 years ago

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The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of

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Answer:

a) 0.0392

b) 0.4688

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 29858, \sigma = 5600$

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20000 - 29858}{5600}$

$Z = -1.76$

$Z = -1.76$ has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

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$Z = 0.02$

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$1.645 = \frac{X - 29858}{5600}$

$X - 29858 = 5600*1.645$

$X = 39070$

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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Step-by-step explanation:

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2 years ago

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