So average is of the first 6 tests is 82 well that means
(test1 + test2+ test3+ test4 + test5+test6)/6 = 82
so now let do some cross multiplliying
test1 + test2 + test3 + test 4 + test5 +test6 = 82*6
test1 + test2 + test3 + test 4 + test5 +test6 = 492
now lets see if we can find that 7th test score
(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5
So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.
(492 + test7 )/7 = 80.5
test7 = (80.5*7)-492 = 71.5
<span>1) The number of subscribers to magazine A in 2000 is 5,000 more than the number of subscribers to magazine B in 2000.
2) Which of the following describes the number of subscribers represented by the tables?
The number of subscribers to both magazines are decreasing.
3) As the number of years since 2000 increases, the number of subscribers both magazines approach zero.</span>
Answer:
am i supposed to do area? volume? circumfrence?
For this case we have a function of the form:
Where,
A: initial amount
b: decrease rate
x: time in years
Substituting values we have:
For 2010 we have:
Answer:
an exponential decay function to model this situation is:
y = 1300 * (0.97) ^ x
The population in 2010 is:
y = 1083
Put the numbers in order
6,7,15,36,41,43,47,49
Q1 = (7 + 15) / 2 = 22/2 = 11 <== first quartile
Q2 = (36 + 41) / 2 = 77/2 = 38.5 <== median
Q3 = (43 + 47) / 2 = 90/2 = 45 <== third quartile
difference of largest value and median.....(49 - 38.5) = 10.5
