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HACTEHA [7]
2 years ago
7

Evaluate the expression. P(9, 3) · P(5, 4)

Mathematics
1 answer:
boyakko [2]2 years ago
6 0

Answer:

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

Step-by-step explanation:

For this problem we want to find the following expressionÑ

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

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Please answer this I really need help, Ariel spent a total of $3.42 buying dried apricots from the bulk bins, which were on sale
Kamila [148]

Answer:

1.2 lbs

Step-by-step explanation:

This problem is set up so that the total price is proportional to the price per pound, so to find the proportion you would divide the total cost by the cost per pound. 3.42/2.85 = 1.2, so the answer is 1.2 pounds.

5 0
1 year ago
Two similar bottles are shown. the smaller bottle can hold 500ml. how much can the larger bottle hold. the smaller bottle is 15
tankabanditka [31]

Answer:

If we assume that the bottle is cylindrical and we take the same radius (3.26) of both the bottles (bottles only differ in heights) then the larger bottle will hold approximately 701.14 ml of fluid (the answer says 700ml which is very close)

Step-by-step explanation:

Step 1: Formula of volume of a cylinder is pi*r^2*h

where value of pi is 3.14

r is the radius

h is the height of the bottle (height is different for both bottles)

After putting the values and estimated radius for both as 3.26, we get the volume of the taller bottle.

You can extract the radius by following this method:

Volume of a cylinder = pi*r^2*h (now put the value of the known volume and height of the smaller cylinder)

500 = 3.14 * (r)^2 *15

500/(3.14*15) = r^2

10.616 = r^2

Taking sqrt. on both sides

We get r = 3.26

Now put the same value in the formula of volume with the radius and height. You will get the answer for second bottle.

V= 3.14 * (3.26)^2 *21

V= 701.14 (approx)

5 0
2 years ago
Read 2 more answers
Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
alekssr [168]
Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

4 0
2 years ago
Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−
poizon [28]

f(t)=\begin{cases}\cos t&\text{for }0\le t

The Laplace transform is then

\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt

Let I denote the integral we want to compute. Integrating by parts, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t

gives

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt

Integrate by parts again, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t

Then

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)

I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I

(s^2+1)I=s(e^{-\pi s}+1)

I=\dfrac s{s^2+1}(e^{-\pi s}+1)

7 0
2 years ago
Which statement is true about the square pyramid below?
Reika [66]

Answer:

b

Step-by-step explanation:

6 0
1 year ago
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