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bearhunter [10]
2 years ago
13

What is the GCF of 16s3t, 40s5, and 68t2? 4 4s3t 8 8s3t

Mathematics
2 answers:
kumpel [21]2 years ago
9 0

Answer:  First option is correct.

Step-by-step explanation:

Since we have given that

16s^3t,40s^5\ and\ 68t^2

First we write the factors of all of these numbers:

Factors of 16s^3t is given by

4\times 4\times s\times s\times s\times t

Factors of 40s^5 is given by

2\times 2\times 2\times 5\times s\times s\times s\times s\times s

Factors of 68t^2 is given by

17\times 2\times 2\times t\times t

So, GCF ( Greatest common factor) will be

2\times 2=4

Hence, First option is correct.

Gemiola [76]2 years ago
3 0
4 is the only factor common among all terms
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Shkiper50 [21]

Answer:

See I don't know the answer but I did another one like this if it doesn't help you can report it no problem

Step-by-step explanation:

There are 2 different ways you can solve this problem and you'll get the same answer.

To help you visualize what you have to do, it might be easiest to translate your problem to a unit that easier to use.

Since you only have a ribbon 5 feet long, but you must cut it into 6 pieces, you know it won't even be 1 foot long.

One way to solve the problem would be to translate your 5-foot ribbon into a ribbon divided into inches.

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To find out how many inches long your ribbon is, you'll need to multiply the number of feet by 12.

Once you know that, then you can more easily divide it by 6. This will tell you how many inches each ribbon is.

Careful! the answer is to be put into feet so once you know how many inches long the ribbon is, you must then divide by 12 to get the correct answer in feet. Don't forget to round to the nearest tenth.

Another way to solve the problem is to simply divide the 5 feet by the number 6 and then round your number to the nearest tenth. It may be harder to visualize the answer this way, but you will get the same answer as if you translated your ribbon into inches and then divided by 12.

Good luck! I hope this helps!

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