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denis23 [38]
2 years ago
13

Daisy is making solid spikes for her Halloween costume. The spikes are shaped like right circular cones with base radius of 2 in

ches and height of 6 inches. If Daisy has 360 cubic inches of material for making the spikes, what is the maximum number of spikes she can make? (Round your answer to the nearest whole number.)
Mathematics
1 answer:
gregori [183]2 years ago
6 0

Answer:

She can make 14 spikes maximum

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Bernardo and Ogechi were asked to find an explicit formula for the sequence 1\,,\,8\,,\,64\,,\,512,...1,8,64,512,...1, comma, 8,
MatroZZZ [7]

Answer:

h_{n}=1.(8)^{n-1} will be the correct formula for the given sequence.

Step-by-step explanation:

The given sequence is 1, 8, 64, 512...........

The given sequence is a geometric sequence having a common ratio (r) of

r = \frac{\text{Second term}}{\text{First term}}

r = \frac{8}{1}=8

Since explicit formula of a geometric sequence is given by

T_{n}=a(r)^{n-1}

where T_{n} = nth term of the sequence

a = first term of the sequence

r = common ratio of the successive term to the previous term

Now we plug values of a and r in the formula to get the explicit formula for the given sequence.

T_{n}=1.(8)^{n-1}

Therefore, if Bernardo is saying that the formula of the sequence is

h(n) = 1.(8)^{n-1} then he is correct.

7 0
2 years ago
Read 2 more answers
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and ob
klio [65]

Answer:

Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.

A.  The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.

C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.

E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake

The answer is E.

6 0
2 years ago
The probabilities of the orphaned pets in six cities' animal shelters being different types of animals are given in the table. I
olga2289 [7]
Given the table below showing t<span>he probabilities of the orphaned pets in six cities' animal shelters being different types of animals.

</span>
   City          Cat          Dog        Dog        Dog       <span>Dog                                      
                         −Lhasa Apso −Mastiff −Chihuahua −Collie
Austin       24.5%      2.76%    2.86%     3.44%    2.65%
Baltimore 19.9%      3.37%    3.22%     3.31%    2.85%
Charlotte  33.7%     3.25%     3.17%     2.89%    3.33%
St. Louis  43.8%     2.65%     2.46%     3.67%    2.91%
Salt Lake
City          28.9%     2.85%     2.78%     2.96%    2.46%
Orlando   37.6%     3.33%     3.41%     3.45%    2.78%
Total        22.9%     2.91%     2.68%     3.09%    2.58%</span><span>

Condtional probability </span><span>is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B).

The probability of A given B, is given by
P(A|B)= \frac{P(A\cap B)}{P(B)}

From the table, the probability that an </span>orphaned pet in a St. Louis animal shelter is a mastiff dog is 2.46% and the probability that <span>an <span>orphaned pet in a St. Louis animal shelter is a dog is 2.91% + 2.68% + 3.09% + 2.58% = 11.26%</span>

The probability that a randomly selected orphaned pet in a St. Louis animal shelter is a mastiff given that it is a dog, is given by
\frac{P(St. \, Louis\, and\, dog-mastiff)}{P(dog)} = \frac{2.46}{11.26} \times100\%=21.85\%</span>
5 0
2 years ago
Read 2 more answers
The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of
miv72 [106K]
L=5/2*2w=5w
P=(5w+w)*2=12w
Perimeter is 12w
7 0
2 years ago
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A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. A fre
JulsSmile [24]

Answer:

SD = 7588.09

Step-by-step explanation:

Check the distribution table attached to for the step by step solution:

The formula for the mean, \bar{x} = \frac{\sum fx}{\sum f}

\bar {x} = \frac{1410040}{80} \\\bar {x} = 17625.5

The variance , V(X) = \sqrt{\frac{\sum f(x - \bar{x}^2)}{n-1} }

V(X) = \frac{4548750000}{80 - 1} \\V(X) = 57579113.92

Standard Deviation,

SD = \sqrt{V(X)} \\SD = \sqrt{57579113.92}

SD = 7588.09

7 0
2 years ago
Read 2 more answers
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