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tatuchka [14]
2 years ago
13

The surface areas of two similar figures are 4 in2 and 9 in2. If the volume of the larger figure is 216 in3, what is the volume

of the smaller figure?
Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0
We know that
surface area smaller figure=scale factor²*surface area larger figure
scale factor=√[surface area smaller figure/surface area larger figure]
scale factor=√[4/9]-----> scale factor=2/3
so
volume smaller figure=scale factor³*volume larger figure
volume smaller figure=(2/3)³*216----> (8/27)*216----> 64 in³

the answer is
the volume of the smaller figure is 64 in³
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se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
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Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
Which equation represents an exponential function with an intitial value of 500? f(x) = 100(5)^x, f(x) = 100(x)^5, f(x) = 500(2)
Leya [2.2K]

Answer:

f(x) = 500(2)^x

Step-by-step explanation:

Let's assume the initial x value is 0

500(0)^2 = 0

100(0)^5 = 0

500(2)^0 = 500

500(0)^2 = 0

6 0
2 years ago
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