-3(y+2)^2-5+6y
-3(y^2+4y+4)-5+6y
-3y^2-12y-12-5+6y
-3y^2-6y-17
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
1. you have to figure out what 3/4 of Ella's time is.

(You find that out by multiplying 5x1. Then add 3.)
2. Convert the fractions into decimals. (This will help make it easier when dividing.)


3. Next you are going to divide 1.6 by .75

4. Now multiple 2.13 by 5.

Answer is 10
Answer:
Out of every 5 trials, the desired outcome will occur approximately 2 times
Step-by-step explanation:
The first statements states that it will happen exactly two times, but probability never guarantee the outcome
The third and fourth statement states out of 7 which cannot be true as 2-5 basically means out of 5