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2 years ago

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Suppose two individuals (smith and jones) each have 10 hours of labor to devote to producting either ice cream (x) or chicken so

up (y). smith's utility function is given by

1 answer:

sattari [20]2 years ago

5 0

It has to be either 10x or 10y

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A coach purchases 47 hats for his players and their families at a total cost of $302. The cost of a small hat is $5.50. A medium

bazaltina [42]

First, we define variables:
x: small hat
y: medium hat
z: large hat
We now write the system of equations:
x + y + z = 47
5.50x + 6y + 7z = 302
-3x + y = 0
We can write the system in matrix form as:
Ax = b
Where,
A = [1 1 1; 5.50 6 7; -3 1 0]
b = [47; 302; 0]
x = [x; y ; z]
Solving the system we have:
x = 6
y = 18
z = 23
Answer:
the coach did purchase 23 large hats
d. 23

3 0

2 years ago

Read 2 more answers

if two points are given,then exactly one line can be drawn through those two points.which geometry term does the statement repre

lubasha [3.4K]

Answer:

This is a postulate which states that through any two points, there is exactly one line.

Step-by-step explanation:

A postulate is a statement that is assumed true without proof.

5 0

2 years ago

Read 2 more answers

The weight of a USB flash drive is 30 grams and is normally distributed. Periodically, quality control inspectors at Dallas Flas

vazorg [7]

Answer:

The critical t values are -1.746 and 1.746.

Step-by-step explanation:

Given information:

The weight of a USB flash drive is 30 grams and is normally distributed.

Population mean = 30

Sample size = 17

Sample mean= 31.9

Standard deviation = 1.8

Significance level, α=0.10

Null hypothesis: $H_0:\mu=30$

Alternative hypothesis: $H_1:\mu\neq 30$

It is a two tailed test.

The t-critical values for a two-tailed test, for a significance level of α=0.1 are -1.746 and 1.746.

Therefore the critical t values are -1.746 and 1.746.

5 0

2 years ago

The following table shows the annual income, in dollars, and amount spent on vacation, in dollars, for a sample of 8 families.

marishachu [46]

Answer:

a. Scatterplot is attached.

b. Positive Correlation

c. Correlation coefficient=0.9219

Step-by-step explanation:

a.

The following procedure will be used to obtain the scatter plot

Open an Google Sheets file online or excel sheet on your computer.
In column B and C, enter the Income and Vacation data as provided above.
Select the data > click on insert CHART.
Chose Scatter Chart option

Click OK.

A scatter plot visualizing your data should be displayed as attached.

b.

On your computer, open a spreadsheet in Google Sheets.
Double-click on your scatter plot.
At the right, click on Customize tab and then Series.
Scroll down and check the Trend line box

-From the trend line, your notice that your variables have a positive correlation.

-As the income increases, so does vacation expenditure.

c. The correlation coefficient can be calculated as follows.

Click on any empty cell in the sheet and enter the formula
"=CORREL((y-axis range),(x-axis range))"
ENTER

-From our Google Sheets calculation our variables have a positive correlation and the correlation coefficient is 0.9219

-The correlation coefficient,r can also be calculated manually:

-let x be income, and y be vacation and divide all the values by 100 to make the smaller and easier to manipulate:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2-(\sum x)^2][n\sum y^2-(\sum y)^2}}\\\\\\\sum xy=153914\\\sum x=4485\\\sum y=246\\\sum x^2=2878447\\(\sum x)^2=4485^2=20115225\\(\sum y)^2=246^2=60516\\\sum y^2=8392\\n=8\\\\\#substitute \ and \ solve \ for \ r\\\\=\frac{8\times153914-4485\times 246}{\sqrt{[8\times 2878447-4485^2][8\times 8392-246^2]}}\\\\=0.92186\\\\\approx 0.9219$

4 0

2 years ago

Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the following data values: 560,

julsineya [31]

Answer:

z-score for value 560 = 0.6

z-score for value 650 = 1.5

z-score for value 500 = 0

z-score for value 450 = -0.5

z-score for value 300 = -2

Step-by-step explanation:

We are given a sample with a mean of 500 and a standard deviation of 100.

i.e., $\mu$ = 500 and $\sigma$ = 100

The z score distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where X represents the data values;

So, z score for value 560 is;

z score = $\frac{560-500}{100}$ = 0.6

So, z score for value 650 is;

z score = $\frac{650-500}{100}$ = 1.5

So, z score for value 500 is;

z score = $\frac{500-500}{100}$ = 0

So, z score for value 450 is;

z score = $\frac{450-500}{100}$ = -0.5

So, z score for value 300 is;

z score = $\frac{300-500}{100}$ = -2

7 0

2 years ago