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stich3 [128]
2 years ago
11

Rootkits are kernel programs having the ability to hide themselves and cover up traces of activities. It replaces certain operat

ing system calls and utilities with its own modified versions of those routines.
Which of the following rootkit modifies the boot sequence of the machine to load themselves instead of the original virtual machine monitor or operating system?
Hypervisor level rootkit
Kernel level rootkit
Boot loader level rootkit
Library level rootkits
Computers and Technology
1 answer:
yawa3891 [41]2 years ago
3 0

Answer:

Boot loader level rootkit

Explanation:

A rootkit is a malicious program which is used by hackers to gain illegal access to the computer system.A bootloader level rootkit also known as bootkit, infects the master boot record(MBR) of the hard drive.As a result bootloader level rootkit is able to compromise the boot process and can modify the boot sequence of the machine to load themselves instead of the original virtual machine monitor or operating system.

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Strlen("seven"); what is the output?
Leokris [45]

Answer:

A is your answer hope this helps

4 0
2 years ago
You are a high school student learning about computers and how to build them. As a class project, you have built a new computer.
Anon25 [30]

Answer:

You can use thermal paste, active heat sink, liquid pipes, and even a fan. These are just some that I've heard.

Explanation:

All of these are cooling and will stop the Central Processing Unit from overheating.

Hope this helps :)

5 0
1 year ago
In Java please:
Nana76 [90]

Answer:

See explaination

Explanation:

public class PalindromeChange {

public static void main(String[] args) {

System.out.println("mom to non palindrom word is: "+changTONonPalindrom("mom"));

System.out.println("mom to non palindrom word is: "+changTONonPalindrom("aaabbaaa"));

}

private static String changTONonPalindrom(String str)

{

int mid=str.length()/2;

boolean found=false;

char character=' ';

int i;

for(i=mid-1;i>=0;i--)

{

character = str.charAt(i);

if(character!='a')

{

found=true;

break;

}

}

if(!found)

{

for(i=mid+1;i<str.length();i++)

{

character = str.charAt(i);

if(character!='a')

{

found=true;

break;

}

}

}

// This gives the character 'a'

int ascii = (int) character;

ascii-=1;

str = str.substring(0, i) + (char)ascii+ str.substring(i + 1);

return str;

}

}

6 0
2 years ago
Emulated drivers provide enhanced drivers for the guest OS and improve performance and functionality for IDE and SCSI storage de
Vikki [24]

Answer:

The answer is "Option 2".

Explanation:

  • All the other drivers replicate even existing technical embedded devices. These systems have optimistic, and they are commonly accessible to inbox operators as most web browsers. It is an Imitated device, that performance problems because of all the emulator is the workload.
  • Integration Services  is a program package, which is created on a guest OS of a VM, that provides enhanced guest OS drivers and improves accuracy, functionality for IDE and SCSI storage systems, networking interfaces, and monitor and multimedia devices, that's why it is incorrect.

8 0
2 years ago
What conclusion can be made about the state of the program when the while loop terminates? Assume answer is a declared and initi
stellarik [79]

<u>Answer:</u>

<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.

<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>

Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.

<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>

Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.

3 0
2 years ago
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