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OlgaM077 [116]
2 years ago
15

the average sneeze can travel 3/100 mile in 3 seconds. at this rate how far can it travel in 1 minute​

Mathematics
2 answers:
GaryK [48]2 years ago
6 0
60/100 of a mile because if in three seconds it goes 3/100 it would mean 1/100 would be one second and one minute is 60 seconds so it would be 60/100 of a mile
shusha [124]2 years ago
4 0

Answer:

0.6 mile

Step-by-step explanation:

Given: The distance traveled in 3 seconds is \frac{3}{100} miles.

To find: The distance it can travel in 1 minute.

Solution: In order to find the distance traveled in 1 minute, first we need to find the distance traveled in 1 second.

In 3 seconds it can travel \frac{3}{100} miles. So, in 1 second it can travel \frac{3}{100\times3} =\frac{1}{100} miles.

Now, we know that in 1 minute there are 60 seconds. So, in 1 minute it can travel

=\frac{1}{100} \times60

=\frac{1}{10} \times6

=\frac{6}{10}

=0.6 mile

Hence, it can travel 0.6 mile in a minute.

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12. A cyclist travels 40 km at a speed of x km/h. Find the time
GREYUIT [131]

Answer:

Step-by-step explanation:

distance = rate times time, so

           

           distance

time = --------------

               rate

Here the distance is 40 km and the rate is x.  Then

              40 km

time = --------------  =  (40/x) hr

             x km/hr

If the speed is reduced by 2 km/hr, we get:

              40 km                                            40 km                  40

time = -------------------------------  or time = ----------------------- = --------- hr

             (x km/hr - 2 km/hr)                      (x - 2) (km/hr)       x - 2

The difference between the times is:

 40          40

-------- - --------- = 1 hr          Solve this for the original speed, x

x - 2         x

40x - 40x + 80                                80

-----------------------  =  1 hr     or     ------------ = 1     or 80 = x^2 - 2x

     x(x - 2)                                     x(x - 2)

Rewriting this in standard quadratic form:  x^2 - 2x - 80 = 0

Here a = 1, b = -2 and c = -80, and so the discriminant b^2 - 4ac is:

(-2)^2 - 4(1)(-80) = 324

The solutions are:

   

      -(-2) ± √324       2 ± 18

x = -------------------- = ------------ = 1 ± 9, or 10 (discard the other root)

              2                      2

The original speed was 10 km/hr

7 0
2 years ago
Read 2 more answers
5. What is the solution to the equation -3(h + 5) + 2 = 4(h + 6) - 9
Klio2033 [76]

Answer: d.h=−4

PLZ MARK BRAINLIEST!

Step-by-step explanation:

Let's solve your equation step-by-step.

−3(h+5)+2=4(h+6)−9

Step 1: Simplify both sides of the equation.

−3(h+5)+2=4(h+6)−9

(−3)(h)+(−3)(5)+2=(4)(h)+(4)(6)+−9(Distribute)

−3h+−15+2=4h+24+−9

(−3h)+(−15+2)=(4h)+(24+−9)(Combine Like Terms)

−3h+−13=4h+15

−3h−13=4h+15

Step 2: Subtract 4h from both sides.

−3h−13−4h=4h+15−4h

−7h−13=15

Step 3: Add 13 to both sides.

−7h−13+13=15+13

−7h=28

Step 4: Divide both sides by -7.

−7h

−7

=

28

−7

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5 0
2 years ago
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If quadrilateral PQRS is a rectangle, then which of the following is true?
brilliants [131]

∠STP ≅ ∠QTR is the True statement ⇒ answer C

Step-by-step explanation:

In any rectangle

1. Each two opposite sides are equal and parallel

2. The measure of its vertex angles is 90°

3. The two diagonals are equal

Now lets find the true statements

∵ PQRS is a rectangle

∴ PS = QR ⇒ opposite sides

∴ PQ = SR ⇒ opposite sides

∴ PR = QS ⇒ diagonals

A.  ∠PSQ ≅ ∠QSR

∵ The diagonals of the rectangle do not bisect the vertex angles

∴ AQ does not bisect angle S

∴  m∠PSQ ≠ m∠QSR

∴  ∠PSQ not congruent ∠QSR

∠PSQ ≅ ∠QSR ⇒ False

B. segment SR ≅ segment RQ

∵ SR and RQ are two adjacent sides

∵ The adjacent side in the rectangle not equal

∴ SR ≠ QR

∴ segment SR not congruent to segment RQ

segment SR ≅ segment RQ ⇒ False

C. ∠STP ≅ ∠QTR

∵ PR intersects QS at point T

∴ m∠STP = m∠QTR ⇒ vertically opposite angles

∴ ∠STP ≅ ∠QTR

∠STP ≅ ∠QTR ⇒ True

D. segment PS ≅ segment PR

∵ PS is a side in the rectangle

∵ PR is a diagonal in the rectangle

∵ The side of the rectangle not equal the diagonal of the rectangle

∴ PS ≠ PR

∴ segment PS not congruent to segment PR

segment PS ≅ segment PR ⇒ False

∠STP ≅ ∠QTR is the True statement

Learn more:

You can learn more about rectangle in brainly.com/question/6594923

#LearnwithBrainly

8 0
2 years ago
Read 2 more answers
Transversal CD←→ cuts parallel lines PQ←→ and RS←→ at points X and Y as shown in the diagram. If m∠CXP = 106.02°, what is m∠SYD?
Softa [21]
<span>m∠SYD = </span>106.02°
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8 0
2 years ago
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PLEASE HELP, I’ve been stuck on this question for a whileIn the diagram, AB is divided into equal parts. The coordinates of poin
castortr0y [4]
AB is divided into 8 equal parts and point C is 1 part FROM A TO B, so the ratio is 1:7, with C being 1/7 of the way.  The ratio is k, found by writing the numerator of the ratio (1) over the sum of the numerator and denominator (1+7).  So our k value is 1/8.  Now we need to find the rise and the run (slope) of the points A and B.  m= \frac{5-9}{9-(-3)}.  That gives us a rise of -4 and a run of 12.  The coordinates of C are found in this formula: C(x,y)=[ x_{1} +k(run), y_{1} +k(rise)].  Filling in accordingly, we have C(x,y)=[-3+ \frac{1}{8}(12),9+ \frac{1}{8}(-4)] which simplifies a bit to C(x,y)=(-3+ \frac{3}{2},9- \frac{1}{2}).  Finding common denominators and doing the math gives us that the coordinates of point C are (- \frac{3}{2}, \frac{17}{2}).  There you go!
3 0
2 years ago
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