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2 years ago

the average sneeze can travel 3/100 mile in 3 seconds. at this rate how far can it travel in 1 minute

2 answers:

6 0

60/100 of a mile because if in three seconds it goes 3/100 it would mean 1/100 would be one second and one minute is 60 seconds so it would be 60/100 of a mile

shusha [124]2 years ago

4 0

Answer:

0.6 mile

Step-by-step explanation:

Given: The distance traveled in 3 seconds is $\frac{3}{100}$ miles.

To find: The distance it can travel in 1 minute.

Solution: In order to find the distance traveled in 1 minute, first we need to find the distance traveled in 1 second.

In 3 seconds it can travel $\frac{3}{100}$ miles. So, in 1 second it can travel $\frac{3}{100\times3} =\frac{1}{100}$ miles.

Now, we know that in 1 minute there are 60 seconds. So, in 1 minute it can travel

$=\frac{1}{100} \times60$

$=\frac{1}{10} \times6$

$=\frac{6}{10}$

$=0.6$ mile

Hence, it can travel 0.6 mile in a minute.

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2 years ago

Read 2 more answers

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Gnom [1K]

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2 years ago

The average blood alcohol concentration (bac) of eight male subjects was measured after consumption of 15 ml of ethanol (corresp

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Answer:

After 5 minutes, the BAC was increasing at the rate of 0.0137 mg/mL a minute.

Step-by-step explanation:

The average blood alcohol concentration (bac) is modeled by the following function.

$c(t) = 0.0225te^{-0.0467t}$

In which t is measured in minuted.

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This is c'(t) when t = 5.

Using the derivative of the product.

Derivative of the product:

$c(t) = f(t)*g(t)$

$c'(t) = f'(t)*g(t) + f(t)*g'(t)$

In which problem:

$f(t) = 0.0225t$

$g(t) = e^{-0.0467t}$

$c'(t) = 0.0225e^{-0.0467t} - 0.0225*0.0467*te^{-0.0467t}$

$c'(5) = 0.0225e^{-0.0467*5} - 0.0225*0.0467*5e^{-0.0467*5} = 0.0137$

After 5 minutes, the BAC was increasing at the rate of 0.0137 mg/mL a minute.

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2 years ago

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2 years ago

the average sneeze can travel 3/100 mile in 3 seconds. at this rate how far can it travel in 1 minute​

the average sneeze can travel 3/100 mile in 3 seconds. at this rate how far can it travel in 1 minute