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2 years ago

“The perimeter P of a triangle is equal to the sum of the lengths of sides a,b, and c”

Mathematics

1 answer:

Kryger [21]2 years ago

5 0

Answer:

1. Write the addition of "a", "b" and "c".

2. The equation is: $P=a+b+c$

Step-by-step explanation:

You know that P represents the perimeter of the triangle and a, b and c represent the sides of the triangle.

By definition, the sum is the result of an addition. Therefore, the statement "The perimeter P of a triangle is equal to the sum of the lengths of sides a, b, and c”, indicates that the perimeter is obtained by adding the lengths of the sides of the triangle.

Knowing this, you can write the following equation:

$P=a+b+c$

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Marvin find doubles facts, such as 4+4 and 1+1,on the addition table. He colors each sum. What pattern does Marvin make when he

adoni [48]

4+4=8 so 1+1=2 that the answer

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2 years ago

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Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the leng

ExtremeBDS [4]

Answer:

<h2>The right option is twelve-fifths</h2>

Step-by-step explanation:

Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

Tan (A) = opp/adj

Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;

tan(A) = BC/AC

tan(A) = 24/10

tan(A) = 12/5

The right option is therefore twelve-fifths

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2 years ago

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Sara borrowed $500 for four years at 3 percent interest, compounded annually. Use the formula to calculate the total amount she

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A=500×(1+0.03)^(4)
A=562.75

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Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t

gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

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2 years ago

2.5 kg of cabbages cost £1.20 Work out the cost of 3.75 kg

s2008m [1.1K]

Thank you for your question!

In order to get the cost of 1 kg of cabbage, divide the cost by the quantity:

1.20/2.5
0.48

Now, multiply the amount for 1 kg to 3.75, because you need 3.75 times the amount.

0.48 * 3.75
1.80

So, it would cost 1.80 pounds for 3.75 kg.
Hope this helped!

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2 years ago