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xz_007 [3.2K]
2 years ago
8

A computer can perform c calculations in s seconds. How many minutes will it take the computer to perform k calculations?

Computers and Technology
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

c calculation =s seconds

1 calculation =s/c seconds

therefore for "k" calculation

k calculation = k*(s/c) seconds

convert it into minutes

k calculation =(k*(s/c))/60 minutes

Explanation:

Since "c" calculation takes "s" seconds by a computer. Then 1 calculation will take "s/c" seconds. If we have to find the time for "k" calculation Then multiply "k" with "s/c".it will give the time for "k" calculation. Then convert it into minutes by dividing 60. This will be the time in minutes for "k" calculation.

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Which of the following is not true of how computers represent complex information
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Answer: c. Depending on context the same sequence of bits may represent different types of information.

Explanation:

The options for the question are:

A. Computing devices use patterns of bits to represent complex information

B. Abstraction helps represent complex information by surfacing complexity that might otherwise be hidden

C. Depending on context the same sequence of bits may represent different types of information

D. Common abstractions that are represented by computing devices include numbers, characters, and color.

The following are true of how computers represent complex information:

• Computing devices use patterns of bits to represent complex information

• helps represent complex information by surfacing complexity that might otherwise be hidden

• Common abstractions that are represented by computing devices include numbers, characters, and color.

Therefore, the option that is not true of how computers represent complex information is that "depending on context the same sequence of bits may represent different types of information".

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2 years ago
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Write a method that accepts a String object as an argument and displays its contents backward. For instance, if the string argum
Nata [24]

Answer:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

}

Explanation:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

}

The program above accepts a String object as an argument and displays its contents backward.

It reverses the any string inputed while producing the output.

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2 years ago
Shirley was unsure about what career to go into. Her high school counselor suggested a personal assessment to point out Shirley’
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Answer:

Answer given below

Explanation:

1.

CREATE VIEW CustomerAddresses AS

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ship.Line1 AS ShipLine1, ship.Line2 AS ShipLine2, ship.City AS ShipCity, ship.State AS ShipState, ship.ZipCode AS ShipZip

FROM Customers custo , Addresses ship , Addresses bill

WHERE custo. BillingAddressID= bill.AddressID AND custo.ShippingAddressID= ship. AddressID;

2.

SELECT CustomerID, LastName, FirstName, BillLine1 FROM CustomerAddresses;

3.

CREATE VIEW OrderItemProducts

AS

SELECT Orders.OrderID, OrderDate, TaxAmount, ShipDate,

ItemPrice, DiscountAmount, (ItemPrice- DiscountAmount) AS FinalPrice,

Quantity, and (Quantity * (ItemPrice-DiscountAmount)) AS ItemTotal,

ProductName FROM

Orders, OrderItems, Products

WHERE

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OrderItems.ProductID = Products. ProductID;

4.

CREATE VIEW ProductSummary

AS

SELECT distinct

ProductName, COUNT(OrderID) AS OrderCount, SUM(ItemTotal) AS OrderTotal

FROM

OrderItemProducts

GROUP BY ProductName;

5.

SELECT ProductName, OrderTotal

FROM ProductSummary P

WHERE 5> (select count(*) FROM ProductSummary S

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ORDER BY OrderTotal;

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Answer:

a

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