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2 years ago

13

gina is making a square tablecloth. what is the least number of inches of trim gina will need to go all the way around the edge

of the tablecloth

1 answer:

boyakko [2]2 years ago

8 0

You need to include the numbers.

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Suppose that 90% of all dialysis patients will survive for at least 5 years. In a simple random sample of 100 new dialysis patie

Keith_Richards [23]

Answer:

The probability $P(\^ p > 0.80) = 0.99957$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.90

The sample size is n = 30

Generally mean of the sampling distribution is $\mu_{\= x } = p = 0.90$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{p( -p )}{n} }$

=> $\sigma = \sqrt{\frac{0.90( 1 -0.90 )}{100} }$

=> $\sigma = 0.03$

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

$P(\^ p > 0.80) = P(\frac{ \^ p - p }{ \sigma } > \frac{0.80 - 0.90}{0.03} )$

Generally $\frac{\^p - p}{\sigma} = Z(The standardized \ value \ of \^ p)$

So

$P(\^ p > 0.80) = P(Z > -3.33 )$

From the z-table $P(Z > -3.33 ) = 0.99957$

So

$P(\^ p > 0.80) = 0.99957$

5 0

2 years ago

47 lbs = ______________ kgs (give answer in decimal form)

Lyrx [107]

"lbs" (pounds) is a measure of force, whereas "kgs" (kilograms) is
a measure of mass. Being different units with different physical
dimensions, they can never be 'equal'.

-- 47 lbs is the weight of 64.9 kgs of mass on Mars.
-- 47 lbs is the weight of 128.8 kgs of mass on the Moon.
-- 47 lbs is the weight of 21.3 kgs of mass on Earth.
.
.
etc.

4 0

2 years ago

Read 2 more answers

The number of cities in a region over time is represented by the function C(x)=2.9(1.05)^x. The approximate number of people per

N76 [4]

Answer:

B. $T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}$

Step-by-step explanation:

The approximate population in the region is the product of the number of cities in a region and the approximate number of people per city, that is:

$T(x) = C(x)\cdot P(x)$ (1)

If we know that $C(x) = 2.9\cdot (1.05)^{x}$ and $P(x) = (1.05)^{3\cdot x + 5}$ , then the formula for the approximate population in the region is:

$T(x) = [2.9\cdot (1.05)^{x}]\cdot [(1.05)^{3\cdot x + 5}]$

$T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}$

Hence, correct answer is B.

3 0

2 years ago

A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen?

Len [333]

Answer:

(a) $Selection = 6724520$

(b) $At\ most\ 12 = 6553976$

(c) $At\ most\ 8 = 6066720$

(d) $At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

Step-by-step explanation:

Given

$Colors = 8$

$Balloons = 28$ --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

$n => 28 + 8-1$ $= 35$

$r = 28$

$Selection = ^{35}^C_{28$

$Selection = \frac{35!}{(35 - 28)!28!}$

$Selection = \frac{35!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29}{7!}$

$Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}$

$Selection = \frac{33891580800}{5040}$

$Selection = 6724520$

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

$n => 15 + 8 -1 = 22$

$r = 15$

Selection of at least 13 =

$At\ least\ 13 = ^{22}C_{15}$

$At\ least\ 13 = \frac{22!}{(22-15)!15!}$

$At\ least\ 13 = \frac{22!}{7!15!}$

$At\ least\ 13 = 170544$

Ways of selecting at most 12 =

$At\ most\ 12 = Total - At\ least\ 13$ --- Complement rule

$At\ most\ 12 = 6724520- 170544$

$At\ most\ 12 = 6553976$

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

$n => 19+ 8 -1 = 26$

$r = 19$

Selection of at least 9 =

$At\ least\ 9 = ^{26}C_{19}$

$At\ least\ 9 = \frac{26!}{(26-19)!19!}$

$At\ least\ 9 = \frac{26!}{7!19!}$

$At\ least\ 9 = 657800$

Ways of selecting at most 8 =

$At\ most\ 8 = Total - At\ least\ 9$ --- Complement rule

$At\ most\ 8 = 6724520- 657800$

$At\ most\ 8 = 6066720$

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

$n =6+6-1 = 11$

$r = 6$

Selection =

$^{11}C_6 = \frac{11!}{(11-6)!6!}$

$^{11}C_6 = \frac{11!}{5!6!}$

$^{11}C_6 = 462$

Using inclusion/exclusion rule of two sets:

$Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 6724520 - 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

3 0

2 years ago

Sabah has $450 to pay for college textbooks. She expects to pay about $75 per book. Her friend told her that 4 of them can be ch

stiks02 [169]

Answer: There are 10 books in all.

Step-by-step explanation:

Let x be the total number of books.

Since we have given that

Amount he paid for college textbooks = $450

Price of each book = $75

Number of books checked out for free = 4

So, Number of books which are not free would be

$\dfrac{450}{75}=6$

So, the total number of books would be

x = Number of books which are not free + Number of books which are free

$x=6+4=10$

Hence, there are 10 books in all.

6 0

2 years ago