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kolbaska11 [484]
2 years ago
13

Suppose a worker needs to process 100 items. The time to process each item is exponentially distributed with a mean of 1 minute,

and the processing times are independent. Approximately, what is the probability that the worker finishes in less than 2.25 hours?
Mathematics
1 answer:
Hunter-Best [27]2 years ago
3 0

Answer: 0.0368

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

P(x)=1-e^{-\lambda x}

, where \lambda is the mean of the distribution.

Given : The time to process each item is exponentially distributed with a mean of 1 minute .

In hour, the mean time to process each item = \lambda=\dfrac{1}{60} hour

Then , the probability that the worker finishes in less than 2.25 hours :-

P(x

Hence, the probability that the worker finishes in less than 2.25 hours = 0.0368

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Is 250% of 44 less than 100, greater than 100 but less than 150, or greater than 150
lakkis [162]

Answer:

It would be greater than 100 and 150. 250% of 44 is negative because 100% of 44 is 0.

Step-by-step explanation:

4 0
1 year ago
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The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

4 0
2 years ago
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Which expression is equivalent to 4/9(2n-3)
krok68 [10]
I hope this helps you out.

5 0
2 years ago
Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
2 years ago
On the planet kudzu, the probability that an animal is blue is 0.20. The probability that the animal has two heads is 0.20. Whic
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Answer:

A.

Step-by-step explanation:

They are dependent events, indicated by the word 'given'.

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