Essa pergunta nao esta em forma ingles, então pessoas nao vao entender.
Answer:
See below
Step-by-step explanation:
See attached for reference
The path has been created by bikers is almost a right triangle with sides of 12, 21 and 24 miles and angles of 61, 89 and 30 deg
a) Biker A travels a straight line (hypotenuse of triangle)
It is likely the bikers meet at the bottom point of the triangle
They make almost same displacement from the start point:
24 miles ≈ √12²+21² miles
b) they meet each other
c) 30 deg
d) e) as per picture attached, it is almost right triangle
f) Together they traveled 12+21+24= 57 miles
Answer:
Your solution is (-10, 6).
Step-by-step explanation:
Combining the equations is also known as substitution. This is done when you substitute one variable into another equation.
-5x + y = 56
x + y = -4
Let's change the second equation into one with one variable on each side.
y = -x - 4
Now, plug this into your first equation.
-5x + (-x - 4) = 56
Distribute the + sign.
-5x - x - 4 = 56
Combine the like terms.
-6x - 4 = 56
-6x = 60
Isolate x by dividing both sides by -6.
x = -10
Now plug this back into either equation.
-10 + y = -4
Add 10 to both sides to find y.
y = 6
Your solution is (-10, 6).
Check this by plugging in these values into the equation you have not checked yet.
-5(-10) + (6) = 56
50 + 6 = 56
56 = 56
Your solution is correct.
Hope this helps!
Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.