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MakcuM [25]
2 years ago
11

The commission earned on the sale of a car can be represented by the equation c(p)=250+0.02p where c represents the commission a

nd p represents the purchase price of a car.
Jack sold two cars last weekend, one for $15,075 and the other for $21,640. Find his total commission.

If c(p)=745.80, find the purchase of the car.
Mathematics
2 answers:
ch4aika [34]2 years ago
6 0

Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

Viefleur [7K]2 years ago
3 0

Answer:

A). Commission = $1234.3

B). Purchase of the car = $24790

Step-by-step explanation:

A).The commission earned on the sale of a car is represented by the equation

C(p) = 250 + 0.02p

Where C represents the commission and p represents the purchase price.

If the purchase price of the car is $15075 then

C(p) = 250 + 0.02 × 15075

       = 250 + 301.50

       = $551.50

If the purchase price of the car was $21640 then

C(p) = 250 + 0.02×(21640)

       = 250 + 432.80

       = $682.80

Therefore, total commission on these cars = $551.50 + $682.80 = $1234.3

B). If C(p) = 745.80 then we have to calculate the purchase of the car.

745.80 = 250 + 0.02p

0.02p = 745.80 - 250

0.02p = 495.80

p = \frac{495.8}{0.02}

  = $24790

Therefore, purchase of the car will be $24790.

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From here we simply need to square root both sides which gives us:

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Hope this helped!

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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y-y1=m(x-x1)

we're going to analyze two cases

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Answer:

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b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

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c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

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So, V = πr²(hr/a)/3

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3aV = πr³h

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Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

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b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

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- ∝πa² ≤ -k divide both sides by - ∝

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