A ship captain is attempting to contact a deep sea diver

Dingane has \$8.00$8.00dollar sign, 8, point, 00, and exactly 30\%30%30, percent of that money is from 555‑cent coins. How many

Ipatiy [6.2K]

If Dingane has $8.00, and thirty percent of that money is from five cent coins, then 8 x 0.3 = $2.40 of Dingane's money is made of five cent coins. In this case the number of five cent coins is the number of cents divided by five: 240/5 = 48. Therefore, Dingane has forty-eight five-cent coins.

6 0

2 years ago

What is the length of segment BD? Round your answer to the nearest hundredth. triangles ABC and ABD in which the triangles share

hichkok12 [17]

Answer:

BD = 4.99 units

Step-by-step explanation:

Consider the triangle ABD only.

The angle formed is 31 degrees which occurs between two sides that are AD and BC.

We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.

Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD

Using formula for tanθ

tanθ = Perpendicular/Base

tan31 = 3/BD

0.601 = 3/BD

BD = 3/0.601

BD = 4.99 units

6 0

2 years ago

Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in

Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of Americans who decide to not go to college = 48%

n = sample of American adults = 331

p = population proportion of Americans who decide to not go to

college because they cannot afford it

Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\hat p-p$ < $1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

90% confidence interval for p = [ $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ , $0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ ]

= [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

$0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }$

$\sqrt{n} = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}$

$\sqrt{n}$ = 54.79

n = $54.79^{2}$

n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

5 0

2 years ago

The probability that Alma makes a three-point shot in basketball is 20 % 20%20, percent. For practice, Alma will regularly shoot

Rainbow [258]

Complete Question: Check the file attached to this document to see the complete question

Answer:

P(X < 7) = 0.76

Step-by-step explanation:

Counting properly from the diagram attached to the question,

number of trials it took her to make less than 7 shots(i.e. 0 to 6 shots) = 38

The total number of trials she made = 50

Probability that it takes fewer than 7 shots to get her first successful shot, P(X < 7) = (number of trials it took to make less than 7 shots)/(Total number of trials)

P(X < 7) = 38/50

P(X < 7) = 0.76

8 0

2 years ago

Nadia draws a portion of a figure, as shown. She wants to construct a line segment through R that makes the same angle with QR a

ch4aika [34]

The answer is C.
Step-by-step explanation:
Given Naoma draws a portion of a figure as shown. She wants to construct a line segment through R that makes the same angle with QR as PQ.
To draw the line we will make sure to draw the same angle as that of the angle between QR and PQ.
Therefore, Owr next step is to measure the angle between QR and PQ with the help of compass in order to draw the same angle & this step is shown in figure C.

Read more on Brainly.com - brainly.com/question/2648041#readmore

8 0

2 years ago

Read 2 more answers