All categories

2 years ago

PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!!!

Mathematics

2 answers:

jok3333 [9.3K]2 years ago

6 0

Answer:

x=9

Step-by-step explanation:

Given information: KM bisects ∠JKL, m∠JKL = 92, and m∠MKL = (5x+1).

It is given that KM bisects ∠JKL. It means line KM divides the angle in two equal parts.

$m\angle JKM=m\angle MKL$ .... (1)

The ∠JKL is the sum of ∠JKM and ∠MKL.

$m\angle JKM=m\angle JKM+m\angle MKL$

Using equation (1) we get

$m\angle JKM=m\angle MKL+m\angle MKL$ $m\angle JKM=m\angle MKL$

$m\angle JKM=2(m\angle MKL)$

Substitute m∠JKL = 92 and m∠MKL = (5x+1) in the above equation.

$92=2(5x+1)$

$92=2(5x)+2(1)$

$92=10x+2$

Subtract 2 from both sides.

$92-2=10x$

$90=10x$

Divide both sides by 10.

$\frac{90}{10}=x$

$9=x$

Therefore, the value of x is 9.

lorasvet [3.4K]2 years ago

5 0

Answer:

x = 9

Step-by-step explanation:

The trick here is knowing that JKM and MKL are equal, which means MKL is equal to JKL/2. From that knowledge, we can solve.

MKL = JKL/2

5x + 1 = 46

5x = 45

x = 9

You might be interested in

Sue played four games of golf.

alisha [4.7K]

Answer:

Sue's scores for the four games in ascending order are: 97, 98, 98, 107

Step-by-step explanation:

Her modal score was 98. The mode is found by using the number that appears most often. This means that 98 has to appear at least two times out of the four scores.

Her range was 10. The range is found by taking the highest score and subtracting it from the lowest score. The highest score had to be greater than 98 and the lowest score had to be less than 98 since we know the mode was 98.

Her mean score was 100. This mean is found by adding all the numbers together and then dividing by the total numbers listed. Adding the four scores together and dividing by 4 will equal 100.

Used guess and test:

Highest Number, 98, 98, Lowest Number

107 - 97 = 10 (meets range requirement)

97 + 98 + 98 + 107 = 400

400/4 = 100 (meets the mean requirement)

7 0

1 year ago

Read 2 more answers

Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi

s2008m [1.1K]

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

7 0

1 year ago

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 105°, a

Akimi4 [234]

Answer:

The area of triangle is $110.10cm^{2}$