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2 years ago

15. Round 4,057 to the nearest hundred

Mathematics

2 answers:

ddd [48]2 years ago

4 0

Answer:

4,100

Step-by-step explanation:

melisa1 [442]2 years ago

3 0

4,100

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A construction company is considering submitting bids for two contracts. It will cost the company \$10{,}000$10,000dollar sign,

baherus [9]

Answer:

0 dollars

=E(M)

=μ

=−$10,000(0.81)+$40,000(0.18)+$90,000(0.01)

=−8,100+7,200+900

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2 years ago

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"A 10-gram marble has a speed that is 5 times as fast as that of a 100-gram marble. Both marbles leave the table at the same tim

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If the 10-gram marble is going faster it is possible that the momentum of the marble will make if go farther than the 100-gram marble

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2 years ago

The points (3,9) and (-3,-9) lie in which quadrants?

kumpel [21]

Answer:

Quadrant I and III

Step-by-step explanation:

The coordinate (3,9) is all positive, therefore it lies in quadrant I.

The coordinate (-3,-9) is all negative, therefore it lies in quadrant III.

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The area of a square concrete slab is 20 square feet. Find the side length of the square concrete slab if the area is increase b

guapka [62]

The side length of the square concrete slab if the area is increased by 25% is 5feet

The formula for calculating the area of a square is expressed as:

A = L² where:

L is the side length of the square

Given the area of the square concrete slab = 20 square feet

20 = L²

L =√20

If the area is increased by 25%, new area will be:

An = 20 + (0.25*20)

An = 20 + 5

An = 25 sq.ft

Get the new length

An = Ln²

25 = Ln²

Ln = √25

Ln = 5feet

Hence the side length of the square concrete slab if the area is increased by 25% is 5feet

Learn more here: brainly.com/question/11300671

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2 years ago

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

Given:

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

Solving the equation:

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

Extraneous solutions:

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

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2 years ago

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