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2 years ago

If M ∠nop = 31 and m ∠NOQ=114 what is m ∠ROQ?

Mathematics

1 answer:

yulyashka [42]2 years ago

4 0

Answer: 83

Step-by-step explanation:

if 31 is m nop and nog is 114 then you subtract 31 from 114

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A standard size bass drum has a diameter of 22 inches and is 18 inches deep. find the volume of the drum

lina2011 [118]

I hope this helps you

5 0

2 years ago

A deli is offering two specials. The roast beef special gives a profit of $2.30 per sandwich, and the turkey special gives a pro

nikklg [1K]

Answer:

The constraints are as follows;

1) 2·x + 2·y ≤ 120

2) 3·x + 4·y ≤ 160

3) x = 2.30

4) y = 3.10

5) P = 2.3·x + 3.10

Step-by-step explanation:

The question is a word problem, with the analysis as follows;

The profit from the roast beef special per sandwich = $2.30

The profit from the turkey special per sandwich = $3.10

The number of slices of bread in the roast beef special = Two slices

The number of slices of cheese in the roast beef special = Three slices

The number of slices of bread in the turkey special = Two slices

The number of slices of cheese in the turkey special = Four slices

The number of slices of bread the deli has = 120 slices

The number of slices of cheese the deli has = 160 slices

Let 'x' and represent the number of roast beef special and 'y' represent the number of turkey special the deli makes, then we have the constraints as follows;

For the number of slices of bread used;

2·x + 2·y ≤ 120...(1)

For the number of slices of cheese used;

3·x + 4·y ≤ 160...(2)

x = 2.30

y = 3.10

The profit 'P' is given by the following equation

P = 2.3·x + 3.10.

5 0

2 years ago

tim estimates that 60÷5.7 is about 10. Will the actual quotient be greater then or less than 10? explain

lana66690 [7]

The actual quotient will be greater than 10 because 60 divided by 5 is 12, so the answer will be between 10 and 12, so it will be greater than 10

7 0

2 years ago

Write 2^60 as an exponent with a base of 8

JulijaS [17]

Answer: 2^60 = 8^20

Step-by-step explanation: 8=2^3

(2^3)^20 Multiply the exponents

3 0

2 years ago

Read 2 more answers

The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. The equation of the circle

Furkat [3]

For an equation to pass through the origin, (0,0) must be a solution of the equation. So, for the first one,

$(x + 12)^{2} + (y + 16)^{2} = r_{1}^{2}$

(0, 0) must satisfy the equation and we can solve for the value of r₁ as shown below.

$(0 + 12)^{2} + (0 + 16)^{2} = r_{1}^{2}$
$12^{2} + 16^{2} = r_{1}^{2}$
$r_{1} = \sqrt{12^{2} + 16^{2}}$
$r_{1} = 20$

Since the second equation of the circle also passes through the origin, we use the same steps from the first one.

$(0 - 30)^{2} + (0 - 16)^{2} = r_{2}^{2}$
$r_{2} = \sqrt{30^{2} + 16^{2}}$
$r_{2} = 34$

Thus, we have the values for r₁ and r₂ as 20 and 34, respectively.

Answer: r₁ = 20 and r₂ = 34

7 0

2 years ago