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joja [24]
2 years ago
4

sam is 3 times as old as Rob. If 15 is subtracted from Sam's age and 13 is added to Rob's age, their ages will be equal. How old

is each now?
Mathematics
2 answers:
Mandarinka [93]2 years ago
7 0

Answer:

Rob's age = 14

Sam's age = 42

Step-by-step explanation:

sam is 3 times as old as Rob.

Let S be the sam's age and R be the Rob's age

S=3R

If 15 is subtracted from Sam's age and 13 is added to Rob's age, their ages will be equal.

S-15=R+13

Replace S with 3R

3R-15=R+13

Subtract R on both sides

2R-15=13

Add 15 on both sides

2R=28

Divide both sides by 2

R= 14

Rob's age = 14

Sam's age = 3(R)= 3(14)= 42

Sam's age = 42

Alexxandr [17]2 years ago
5 0

Answer:

Sam is 42 years old and Rob is 14 years old.

Step-by-step explanation:

x = Rob's age

3x = Sam's age

3x - 15 = x + 13

3x - x = 13 + 15

2x = 28

x = 14

Check:  If you subtract 15 from Sam's age and add 13 to Rob's age they would both be 27.

3(14) - 15 = 14 + 13

42 - 15 = 27

27 = 27

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