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GaryK [48]
2 years ago
13

Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches. What is

the probability that a randomly selected male is more than 74 inches tall? Enter you answer in decimal form, e.g. 0.68, not 68 or 68%.
Mathematics
1 answer:
NNADVOKAT [17]2 years ago
6 0

Answer:

The probability that the man is greater than 74 inches is 0.1587

Step-by-step explanation:

The required probability is found by evaluating the area under the corresponding distribution curve for the corresponding values

The standard normal variate factor (Z) is given by

Z=\frac{x-\bar {X}}{\sigma }

where

\bar{x} is mean of the data

\sigma is the standard deviation of the data

Thus corresponding to x = 74 the Z factor equals

Z=\frac{74-70}{4}=1

Using the standard normal distribution table corresponding to mean of 70 and deviation of 4 the area under the curve corresponding to Z = 1 equals

0.1587

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The measure of the interior angle is the half-sum of the arcs comprising it and its opposite.

so

<u>Find the measure of the angle LAM</u>

m∠LAM is equal to

\frac{1}{2}*[arc\ KJ+arc\ LM]= \frac{1}{2}*[170+80]\\\\=125\ degrees

<u>Find the measure of the angle MAJ</u>

we know that

m∠LAM+m∠MAJ=180° ------> by supplementary angles

m∠MAJ=(180-125)

m∠MAJ=55°

therefore

<u>the answer is</u>

The measure of the angle MAJ is 55\ degrees

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Five students divided 74 base-ten rods equally among them. how many base-ten rods were left over?
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Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

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Let us find area of walls and ceiling.

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Therefore, the combined total cost of tiles and paint is $924.

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