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True [87]
2 years ago
13

On a number​ line, suppose point E has a coordinate of 2​, and EGequals5. What are the possible coordinates of point​ G?

Mathematics
1 answer:
Ivan2 years ago
6 0

Answer:

-3, 7

Step-by-step explanation:

EG = 5, so the distance between E and G is five.

G can be 5 units to the right of E:

2 + 5 = 7

G has coordinate 7.

G can be 5 units to the left of E:

2 - 5 = -3

G has coordinate -3.

Answer: -3, 7

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ms.wright had 7/8 quart of berries. she used 1/3 of the berries to make a fruit salad. she used the rest to make turnovers. what
sweet [91]

Answer:

the answer is 13/24 turnovers

5 0
2 years ago
HELP ME
Vladimir79 [104]
Alrighty, so, if I remember correctly: For the first question you have 20 possible outcomes, 4 of which are multiples of 5. (5,10,15,20). This gives you 4/20, I multiplied both the numerator and denominator by 200 which then gave me 800/4000. Next I divided which gave me 0.2.
6 0
2 years ago
Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

7 0
2 years ago
Read 2 more answers
What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi. (4
saveliy_v [14]

Answer: 19,461\ ft^3

Step-by-step explanation:

The missing figure is attached.

The volume of grain that could completely fill this silo is the sum of the volume of the cylinder and the volume of the hemisphere.

By definition, the volume of a cylinder can be calculated with this formula:

V_c=\pi r^2h

Where "r" is the radius and "h" is the height.

In this case you know that:

r=6\ ft\\\\h=168\ ft

And the volume of a hemisphere can be found using the following formula:

V_h=\frac{2}{3} \pi r^3

Where "r" is the radius.

In this case:

r=6\ ft

Therefore, the volume of grain that could completely fill this silo, rounded to the nearest whole number, is:

V_{grain}=(\frac{22}{7})(6\ ft)^2 (168\ ft)+\frac{2}{3} (\frac{22}{7})(6\ ft)^3\\\\V_{grain}\approx19,461\ ft^3

3 0
2 years ago
Solve the compound inequality. Graph the solution set.<br> -2x&lt;2x-4&lt;4
Arte-miy333 [17]
I hope this helps you

-2x <2x-4

4 <4x

1 <x

2x-4 <4

2x <8

x <4

1 <x <4
5 0
2 years ago
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