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2 years ago

Cassius walked 6 tenths of a 3.6-mile trail.

Mathematics

2 answers:

dolphi86 [110]2 years ago

7 0

Answer:

a. $1.44\ miles$

b. $3.46\ miles$

Step-by-step explanation:

You know that the total length of the trail is 3.6 miles.

a. According to the information provided in the exercise, Cassius walked 6 tenths ( $\frac{6}{10}$ ) of 3.6 miles. This is:

$(3.6\ miles)(\frac{6}{10})=2.16\ miles$

Therefore, you must subtract 3.6 miles and 2.16 miles in prder to calculate the amount of miles Cassius had left to hike:

$3.6\ miles-2.16\ miles=1.44\ miles$

b. You know that Cameron was 1.3 miles ahead of Cassius.

Then, to find the amount of miles Cameron already hiked, you must add 2.16 miles and 1.3 miles.

Therefore, you get:

$2.16\ miles+1.3\ miles=3.46\ miles$

brilliants [131]2 years ago

6 0

Answer:

distance left to hike by cassius is 1.44 miles

Cameron hiked 3.5986 miles

Step-by-step explanation:

Cassius walked 6/10th of trail of 3.6 mile.

Part of the trail remaining = 1 - 6/10 = 4/10 = 2/5

Distance remaining will be 2/5 of 3.6 miles i.e 1.44 miles.

Hence distance left to hike by cassius is 1.44 miles

b. Total distance by which Cameron was ahead of cassius = 1.3 miles.

Distance left to hike by Cameron = 1.44 miles - 1.3 miles = 0.0014 miles.

so, distance hiked by Cameron = 3.6 miles - 0.0014 miles = 3.5986 miles.

Cameron hiked 3.5986 miles.

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