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2 years ago

Which represents a function?

Mathematics

2 answers:

trapecia [35]2 years ago

5 0

The answer is B. Edge 2020.

Explanation: I got it right on my assignment.

Igoryamba2 years ago

4 0

Answer:

StartSet (negative 8, negative 2), (negative 4, 1), (0, negative 2), (2, 3), (4, negative 4) EndSet

Step-by-step explanation:

The function is when there are sets of input and output values given and each input value hem has one corresponding output. Input values are unique but output values can be same for more than one input value.

A.........................................

A 2-column table with 5 rows. The first column is labeled x with entries negative 5, negative 3, negative 3, 0, 5. The second column is labeled y with entries 10, 5, 4, 0, negative 10.

Not a function as input values repeated: negative 3

B.........................................

StartSet (negative 8, negative 2), (negative 4, 1), (0, negative 2), (2, 3), (4, negative 4) EndSet

Yes, it is a function

C.........................................

A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 0, 1. The second column is labeled y with entries negative 3, negative 2, negative 1, 0, negative 1.

Not a function as input values repeated: 0

D.........................................

StartSet (negative 12, 4), (negative 6, 10), (negative 4, 15), (negative 8, 18), (negative 12, 24) EndSet

Not a function as input values repeated: negative 12

<h3>So correct one is option B</h3>

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The probability of a student scoring 75% in class work is 0.64, and the probability of a student scoring 85% is 0.45.

Tresset [83]

Answer: The probability of a student scoring 75%, given that they have already scored 85% in class work is 1.

Step-by-step explanation: Given,

$P(A)=0.64$

and

$P(B)=0.45$ .

Also,

If the student already scored 85%, the it is sure that he/she will definitely score 75%. Hence, the statement that the probability of a student scoring 75% in a class work, given that they already scored 85% is 1 is a true statement.

So, the second statement is true.

6 0

2 years ago

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Mrs.Steﬀen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin

qaws [65]

Answer:

a. $\\ 10! = 3628800$ ;

b. $\\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}$

Step-by-step explanation:

We need here to apply the Multiplication Principle or the Fundamental Principle of Counting for each answer. Answer b needs an extra reasoning for being completed.

The Multiplication Principle states that if there are n ways of doing something and m ways of doing another thing, then there are n x m ways of doing both (Rule of product (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are ten students. When one is selected, there is no other way to select it again. So, no repetition is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is why the Multiplication Principle is important here.

This could be expressed mathematically using n!:

$\\ n! = n * (n-1)! * (n-2)! *...* 2*1.$

For instance, $\\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.$

So, for the case in question, the ten students can line up in:

$\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800$ ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy only the following places in forming the file:

$\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th}$ places.

The members of Group 2 only:

$\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th}$ places.

And the members of Group 3, the following only ones:

$\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th}$ places.

Well, having into account these possible places for each member of G1, G2 and G3, there are: 10! ways for lining up members of G1; 10! ways for lining up members of G2 and, also, 10! ways for lining up members of G3.

After using the Multiplication Principle, we have, thus:

$\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19}$ ways the students can line up to come in from recess.

3 0

2 years ago

The rate of change in revenue for Under Armour from 2004 through 2009 can be modeled by dR /dt = 13.897t + 284.653 t where R is

MakcuM [25]

Answer:

The revenue is $R(9) = \$ 876.9$

Step-by-step explanation:

From the question we are told that

The rate of change in revenue for Under Armour from 2004 through 2009 is

$\frac{d R }{dt } = 13.897t + \frac{284.653}{t}$

Now

$dR = (13.897t + \frac{284.653}{t})dt$

Integrating both sides to obtain R(t)

$\int\limits dR = \int\limits (13.897t + \frac{284.653}{t})dt$

$\int\limits dR = \int\limits (13.897\frac{t^2}{2} + 284.653(ln (t)) ) + C$

=> $R(t) = 6.9485t^2 + 284.653(ln (t) ) + C$

From the question we have that at t = 8 $R(8)= \$ 725.2 \ million$

$725.2 = 6.9485(8)^2 + 284.653(ln (8) ) + C$

=> $C = -311.4$

$R(t) = 6.9485t^2 + 284.653(ln (t) ) -311.4$

At t = 9

$R(9) = 6.9485*(9)^2 + 284.653(ln (9) ) -311.4$

$R(9) = \$ 876.9$

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2 years ago

Each month, a retail store awards a blue ribbon to its employee of the month. The probability that Chloe is the employee of the

Alexxx [7]

P(E)= 29/100 * 49/100 = 0.1421= 14.21%

7 0

2 years ago

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There are 18 people waiting in the bus queue. Half of them are going to Langdale How many people are going to Langdale

Ludmilka [50]

If you would like to know how many people are going to Langdale, you can calculate this using the following steps:

18 people
half of them: 18/2 = 9 people

Result: 9 people are going to Langdale.

6 0

2 years ago

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