Sample response: <span>Yes, the fan will provide enough airflow. The volume of the ranger station is 720 cubic feet. The ranger station requires a 720 CFM fan. 1,500 CFM is greater than 720 CFM, so it will be enough airflow.</span>
Answer:
Yes, the relationship between x and y is a non-linear function.
Step-by-step explanation:
Given the table
Edge Length, x Surface Area, y
1 6
2 24
3 54
4 96
- The table values clearly represent a function, because each input value has one and only one output value. i.e. there is no repetition of x values.
- Also from the table values and the graph, it is clear that the function is not a linear function, because the graph is not a straight line. Also, In a cubic function, the highest power over the x variable(s) is 3. So, it is not a linear function.
Hence, we conclude that Yes, the relationship between x and y is a non-linear function.
Therefore, the 'last option' is correct.
Answer:
Kindly check explanation
Step-by-step explanation:
From the relative frequency below:
For NORTH - SOUTH:
Monday - Thursday = 115 ; has a relative frequency of 75.16%,
Hence, we can obtain the row total since it amounts to 100% thus;
75.16% of row total = 115
0.7516× row total = 115
Row total = 115 / 0.7516 = 153.00
Hence, Friday - sunday:
Row total - (Monday-Thursday)
153 - 115 = 38
FOR EAST - WEST:
Monday - Thursday = 21 ; has a relative frequency of 25.30%,
Hence, we can obtain the row total since it amounts to 100% thus;
25.30% of row total = 21
0. 253 × row total = 21
Row total = 21 / 0.253 = 83.00
Hence, Friday - sunday:
Row total - (Monday-Thursday)
83 - 21 = 62
x = (38 / 100) × 100%
x = 0.38 × 100%
x = 38.00 %
Answer:
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Step-by-step explanation:
Intern No. of Breast
Number Exams Performed X²
1 30 900
2 40 1600
3 8 64
4 20 400
5 26 676
6 35 1225
7 35 1225
8 20 400
9 25 625
<u>10 20 400 </u>
<u> </u><u> ∑ 259 ∑ 7515</u>
Mean= X`= ∑x/n= 259/10= 25.9
Variance = s²= 1/n-1[∑X²- (∑x)²/n]
= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]
= 806.9/9=89.655= 89.66
Standard Deviation= √89.655= 9.4687
Hence
The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262
The 95 % Confidence interval is given by
x`±t(∝,n-1) s/√n
So Putting the values
25.9± 2.262( 9.4687/√10)
= 25.9 ±2.262 (2.9943)
= 25.9 ± 6.7730
= 25.9 +6.7730=32.6730
25.9 -6.7730= 19.1269
= 19.1269, 32.6730
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
I really want to help but I don’t know the answer, sorry
