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Rina8888 [55]
2 years ago
9

A pump with a 400 mm diameter suction pipe and 350 mm diameter discharge pipe is to deliver 20,000 litres per minute of 15.60C w

ater. Calculate the pump head in metres if suction gage is 7.5 cm below the pump centreline and reads 127 mmHg vacuum and the discharge gage is 45 cm above the pump centre line and reads 75 kPa.
Engineering
1 answer:
Svetach [21]2 years ago
7 0

Answer:

pump head is 10.15 m

Explanation:

given data

diameter suction = 400 mm

diameter discharge = 350 mm

discharge = 20000 l/m

to find out

pump head in meters

solution

we know discharge is 20000 l/m

so discharge = \frac{1}{3} m³/min

and

we know suction head hs  is express as

hs = section gauge × specif gravity of Hg

hs = 0.127 × 13.6

hs = 1.7272 m of water

and

delivery head hd is express as

hd = \frac{delivery gauge}{density of water*g}

hd = \frac{75*10^3}{1000*9.81}

hd = 7.6453 m of water

and

we know distance between the gauge is here

Distance D = 0.075 + 0.45 = 0.525 m

so

discharge velocity vd is express as

Vd = \frac{discharge}{area}

Vd = \frac{1}{3*\frac{\pi }{4} * 0.35^2}

Vd = 3.465 m/s

and

suction velocity Vs is express as

Vs = \frac{discharge}{area}

Vs =  \frac{1}{3*\frac{\pi }{4} * 0.4^2}

Vs = 2.653 m/s

so

pump head will be here

pump head = hs + hd + D + \frac{Vd^2 - Vs^2}{2g}

pump head = 1.7272 + 7.6453 + 0.525 +  \frac{3.465^2 - 2.653^2}{2*9.81}

so pump head = 10.15 m

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ELEN [110]

Answer:

I hope it is correct.....

5 0
2 years ago
A 60-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of g/4. Determine
Anuta_ua [19.1K]

Answer:

force R = 846.11 N

lifting force L = 110.36 N

if cable fail complete both R and L will be zero

Explanation:

given data

mass woman mw = 60 kg

mass package mp = 9 kg

accelerates rate a = g/4

to find out

force R and lifting force L and if cable fail than what values would R and L acquire

solution

we calculate here first reaction R force

we know elevator which accelerates upward

so now by direction of motion , balance the force that is express as

R - ( mw + mp ) × g = ( mw + mp ) × a

here put all these value and a = g/4 and use g = 9.81 m/s²

R - ( 60 + 9 ) × 9.81 = ( 60 + 9  ) × g/4

R = ( 69  ) × 9.81/4  + ( 69 ) 9.81

R = 69  ( 9.81 + 2.4525 )

force R = 846.11 N

and

lifting force is express as here

lifting force = mp ( g + a)

put here value

lifting force = 9 ( 9.81 + 9.81/4)

lifting force L = 110.36 N

and

we know if cable completely fail than body move free fall and experience no force

so both R and L will be zero

5 0
2 years ago
Fix the code so the program will run correctly for MAXCHEESE values of 0 to 20 (inclusive). Note that the value of MAXCHEESE is
GarryVolchara [31]

Answer:

Code fixed below using Java

Explanation:

<u>Error.java </u>

import java.util.Random;

public class Error {

   public static void main(String[] args) {

       final int MAXCHEESE = 10;

       String[] names = new String[MAXCHEESE];

       double[] prices = new double[MAXCHEESE];

       double[] amounts = new double[MAXCHEESE];

       // Three Special Cheeses

       names[0] = "Humboldt Fog";

       prices[0] = 25.00;

       names[1] = "Red Hawk";

       prices[1] = 40.50;

       names[2] = "Teleme";

       prices[2] = 17.25;

       System.out.println("We sell " + MAXCHEESE + " kind of Cheese:");

       System.out.println(names[0] + ": $" + prices[0] + " per pound");

       System.out.println(names[1] + ": $" + prices[1] + " per pound");

       System.out.println(names[2] + ": $" + prices[2] + " per pound");

       Random ranGen = new Random(100);

       // error at initialising i

       // i should be from 0 to MAXCHEESE value

       for (int i = 0; i < MAXCHEESE; i++) {

           names[i] = "Cheese Type " + (char) ('A' + i);

           prices[i] = ranGen.nextInt(1000) / 100.0;

           amounts[i] = 0;

           System.out.println(names[i] + ": $" + prices[i] + " per pound");

       }        

   }

}

7 0
2 years ago
(a) If 15 kW of power from a heat reservoir at 500 K is input into a heat engine with an efficiency of 37%, what is the power ou
julsineya [31]

Answer:

(A) Power output will be 5.55 KW (b) lower temperature will be 315 K

Explanation:

We have given efficiency of heat engine \eta =37% = 0.37

Input power = 15 KW

Temperature of heat reservoir T_H=500K

(A) We know that \eta =\frac{output}{input}

So  [text]0.37=\frac{output}{15}[text]

Output = 5.55 KW

(B) We also know that [text]\eta =1-\frac{T_L}{T_H}0.37=\frac{output}{15}[text], here T_L  is lower temperature and T_H is higher temperature

So 0.37=1-\frac{T_L}{T_H}

0.37=1-\frac{T_L}{500}

T_L=315K

5 0
2 years ago
Twenty distinct cars park in the same parking lot every day. Ten of these cars are US-made, while the other ten are foreign-made
Zina [86]

Answer:

Total no. of ways to line up cars is 20! = 2.43 c 10^18

Probability that the cars alternate is 0.00001 or 0.001%

Explanation:

Since, the position of a car is random.Therefore, number ways in which cars can line up is given as:

<u>No. of ways = 20! = 2.43 x 10^18</u>

For the probability that cars alternate, two groups will be formed, one consisting of US-made 10 cars and other containing 10 foreign made. The number of favorable outcomes for this can be found out as the arrangements of 2! between these groups multiplied by the arrangements of 10! for each group, due to the arrangements among the groups themselves.

Favorable Outcomes = 2! x 10! x 10!

Thus the probability of event will be:

Probability = Favorable Outcomes/Total No. of Ways

Probability = (2! x 10! x 10!)/20!

<u>Probability = 0.00001 = 0.001%</u>

4 0
2 years ago
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