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wel
2 years ago
6

You make a phone call to your local electricity company with a question about

Computers and Technology
1 answer:
lisabon 2012 [21]2 years ago
4 0

Answer:

A. Keeping valuable staff.

Explanation:

When I make the call to the local electricity company asking about my most recent bill.My call was passed to department to department before getting a representative who can address my queries.The CRM component that needs to be addressed so that the contact is less-time consuming is keeping he valuable staff.

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The establishment called ABC Enterprise requires a Java program to keep a database of the inventory of the products that it sell
Alexandra [31]

Answer:

// GetData.java

import javax.swing.JOptionPane;

public class GetData

{

  public static double getDouble(String s)

  {

      return Double.parseDouble(getWord(s));

  }

  public static int getInt(String s)

  {

      return Integer.parseInt(getWord(s));

  }

  public static String getWord(String s)

  {

      return JOptionPane.showInputDialog(s);

  }

  public static String getString(String s)

  {

      return JOptionPane.showInputDialog(s);

  }

}

// Address.java

public class Address

{

  private String street, city, state, zip;

  public Address(String str, String city, String st, String zip)

  {

      street = str;

      this.city = city;

      state = st;

      this.zip = zip;

  }

  public String getStreet()

  {

      return street;

  }

 

  public String getCity()

  {

      return city;

  }

  public String getState()

  {

      return state;

  }

  public String getZip()

  {

      return zip;

  }

}

// Manufacturer.java

public class Manufacturer

{

  private String companyName;

  private Address companyAddress;

 

  public Manufacturer()

  {

      this.companyName = "";

      this.companyAddress = null;

  }

 

  public Manufacturer(String compName, Address address)

  {

      this.companyName = compName;

      this.companyAddress = address;

  }

 

  public String getCompanyName()

  {

      return companyName;

  }

 

  public void setCompanyName(String companyName)

  {

      this.companyName = companyName;

  }

 

  public Address getCompanyAddress()

  {

      return companyAddress;

  }

 

  public void setCompanyAddress(Address address)

  {

      this.companyAddress = address;

  }

}

// Product.java

import java.text.SimpleDateFormat;

import java.util.Date;

public class Product

{

 

  SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");

 

 

  Manufacturer manufacture;

 

 

  String productName;

 

 

  int quantity;

 

 

  double unitPrice;

 

 

  Date productCreated;

 

 

  public Product()

  {

      this.productName = "";

      this.quantity = 0;

      this.unitPrice = 0.0;

      this.productCreated = null;

      this.manufacture = null;

  }

 

  public Product(String prodName, int quantity, double unitPrice,

                        Date productCreated, Manufacturer manufact)

  {

      this.productName = prodName;

      this.quantity = quantity;

      this.unitPrice = unitPrice;

      this.productCreated = productCreated;

      this.manufacture = manufact;

  }

 

 

  public Date getProductCreated()

  {

      return productCreated;

  }

 

 

  public void setProductCreated(Date productCreated)

  {

      this.productCreated = productCreated;

  }

 

  // to get the Manufacturer object

  public Manufacturer getManufacture()

  {

      return manufacture;

  }

 

  // to set the Manufacturer object

  public void setManufacture(Manufacturer manufacture)

  {

      this.manufacture = manufacture;

  }

 

  // to get the name of the product

  public String getProductName()

  {

      return productName;

  }

 

  // to set the name of the product

  public void setProductName(String prodName)

  {

      this.productName = prodName;

  }

 

  // to get the quantity of the product

  public int getQuantity()

  {

      return quantity;

  }

 

  // to set the quantity of the product

  public void setQuantity(int quantity)

  {

      this.quantity = quantity;

  }

 

  // to get the unit price of the product

  public double getUnitPrice()

  {

      return unitPrice;

  }

 

  // to set the unit price of product

  public void setUnitPrice(double unitPrice)

  {

      this.unitPrice = unitPrice;

  }

 

  // to update the quantity of the product

  public void upDateQuantity(int quantity_upDate)

  {

      quantity += quantity_upDate;

  }

 

  // to update the price of the product

  public void upDatePrice(double price_upDate)

  {

      this.unitPrice = price_upDate;

  }

 

 

  public String getProductInfomation()

  {

      String result = "";

      result += String.format("%-30s", productName);

      String dateForm = sdf.format(productCreated);

      result += String.format("\t %s", dateForm);

      result += String.format("%10d", quantity);

      result += String.format("\t%15.2f", unitPrice);

      result += String.format("\t%15s",

                          manufacture.getCompanyName());

      result += String.format("\t%20s",

                 manufacture.getCompanyAddress().getState());

      return result;

  }  

}

Explanation:

  • Create a manufacturer class to store and get information about company name and company address.
  • Create a product class to hold the manufacturer object, product name and other relevant information.
4 0
1 year ago
Exponentiation Is a/an operater?​
garik1379 [7]

Answer:

Yes it is

Hope this helps

5 0
1 year ago
Use the values in the range A7:A8 to extend the list of years to the range A9:A11. 3. Use AutoFill to fill the range A9:H11 with
jok3333 [9.3K]

Answer:

Question is incomplete and it needs a proper XL sheet image and more details. I have assumed and answered this question.

1. Use the values in the range A7:A8 to extend the list of years to the range A9:A11

Ans : <em>Use Ctrl + select A7: A8 and drag till A9: A11 : This will extend the list </em>

<em />

<em>2. </em>Use AutoFill to fill the range A9:H11 with the formatting from the range A7:H8.

Ans : Apply format immediately to the cells A9: H11 below with the help of Auto Fill Handle. Using Auto fill button we can able to a cell format to the cell bellow of active cell by just double clicking on the auto fill button.

3. In cell B8, create a formula without using a function that multiplies the value in cell B7 by the value in cell B6 and then adds the value in B7. Update the cell reference to cell B6, from a relative reference to a mixed reference by making an absolute reference to row 

Ans : =($B7*$B6)+$B7

4. Copy the formula from cell B8 to the range B9:B11 and then copy the formulas from the range B8:B11 to the range C8:H11.

Ans:

1. Select the cell B8 that contains which has formula to be copied

2. Click inside the formula bar to activate it and select the entire formula by using mouse and keyboard.

3. Copy the selected formula and press Esc to deactivate the formula bar.

4. Select the cell  B9 : B11 in which you want the copy of the formula to appear.

5. Most range names refer to absolute cell references. This means that when you copy a formula that uses a range name, the copied formula will use the same range name as the original.

6. Paste the formula by using references.

7. Repeat the steps of 1 to 6 for B8:B11 for range C8:H11.

5. Switch to the Cost Estimates worksheet. In cell A9, create a formula using the AVERAGE function that calculates the average of the values in the range A5:A7, then copy your formula to cell D9.

Ans : =AVERAGE(A5:A7) and Copy it to D9 using answer given in 4.

Explanation:

8 0
1 year ago
. Create a text file that contains your expenses for last month in the following categories: • Rent • Gas • Food • Clothing • Ca
Whitepunk [10]

Answer:

  1. from matplotlib import pyplot as plt
  2. with open("text.txt") as file:
  3.    data = file.readlines()
  4.    category = []
  5.    amount = []
  6.    for row in data:
  7.        values = row.split(" ")
  8.        category.append(values[0])
  9.        amount.append(float(values[1]))
  10.    
  11. figure = plt.figure()
  12. ax = figure.add_axes([0,0,1,1])
  13. ax.axis('equal')
  14. ax.pie(amount, labels = category, autopct='%1.2f%%')
  15. plt.show()

Explanation:

Firstly, we need to import matplotlib library (Line 1).

Next, open a file stream and use readlines method to read the data from the text file (Line 4). Presume the data read from the text files are as follows:

Rent 450

Gas 150

Food 500

Clothing 120

Car 600

Create two lists, category and amount (Line 5-6). Use a for loop to traverse through the read data and use split method to break each row of data into two individual items. The first item is added to category list whereas the second item is added to amount list (Line 7 - 10).

Next, create a plot figure and then add the axes (Line 12 - 13). We can use the pie method to generate a pie chart (Line 15) by setting the amount list as first argument and category list as value of labels attributes. The output pie chart can be found in the attachment.

7 0
2 years ago
We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0
2 years ago
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