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kobusy [5.1K]
2 years ago
8

Mrs. Lofton created a histogram of her first two test grades for her class. If she combines the two tests, what percentage of th

e
grades were below 70

Mathematics
1 answer:
umka2103 [35]2 years ago
8 0

Answer:

14.29%

Step-by-step explanation:

Let's do the count for Test #1:

2 + 5 + 6 + 1 = 14 total students

Out of which, below 70 is  2 people [only the leftmost bar]

Let's do the count for Test #2:

2 + 3 + 5 + 4 = 14 total students

Out of which, below 70 is again 2 people [only the leftmost bar]

So, to find percentage of people below 70, we divide the below 70 number of people with total number of people.

(2+2)/(14+14) = 4/28 = 14.29%

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Step-by-step explanation:

From the question x is the number of stools and y is the number of recliners

Given that the coffee shop can hold no more than 50, then the inequality for number of seats will be;

x+y≤ 50

Also, the owner wants at least 20 of the seats to be stools, this can be written as;

x≥20

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A watch company is developing packaging for its new watch. The designer uses octagons with a base area of 30 in2 and rectangles
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Volume of the prototype is 250 in.³

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3 0
2 years ago
Which expression is equivalent to the one below ?
maks197457 [2]

Answer: \frac {X^6 \times Y^4}{X \times Y^2}          

Step-by-step explanation:

<u>1.SEPARATE THE VARIABLES AS X & Y IN NUMERATOR</u>

 NOW,we can changes in the numerator  variable  ADDING THE POWERS THEN THE VARIABLES    X^{2+4} \times Y^{3+1}{/tex]                                            [tex] X^{6} \times Y^{4}{/tex]2. KEEP THE DENOMINATOR AS ITS :                         [tex]X \times Y^{2}

7 0
2 years ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
2 years ago
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