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denis-greek [22]
2 years ago
11

A watch company is developing packaging for its new watch. The designer uses octagons with a base area of 30 in2 and rectangles

with a length of 10 in to create a prototype for the new package. What is the volume of the prototype?
140 in3

200 in3

240 in3

300 in3
Mathematics
2 answers:
posledela2 years ago
6 0

Answer:  300 in3

Step-by-step explanation: To find the volume you multiply the base area by the height. 30 x 10 = 300. Did this for my exam and got the question correct.

bezimeni [28]2 years ago
5 0

Answer:

It's (C) 240in3

Step-by-step explanation:

Volume of the prototype is 250 in.³

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Determine whether the dilation from the figure on the left to the figure on the right is an enlargement or a reduction. Then fin
dybincka [34]

Answer:

A.

Step-by-step explanation:

we are going from a large shape to a smaller shape. the proof is that the side lengths go down from 7m to 0.5m. so, it is a reduction.

and the scaling factor s ? what do we need to multiply the original side lengths with to get the new ones ?

7 × s = 0.5 = 1/2

s = (1/2)/7 = (1/2)/(7/1) = (1×1)/(2×7) = 1/14

=> answer A is correct

8 0
2 years ago
In mathematics, the Nth harmonic number is defined to be 1 + 1/2 + 1/3 + 1/4 + ... + 1/N. So, the first harmonic number is 1, th
Andreyy89

Answer:

cl   +   1/(N+1)

Step-by-step explanation:

If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl

And we know that the (N+1)th harmonic number can be found by doing

1+1/2+1/3+1/4+...+1/N+1/(N+1)

=cl    +   1/(N+1)

The (N+1)th harmonic number is cl   +   1/(N+1) given that the Nth term is cl

Other way to see the answers:

Maybe you want to write it as a single fraction so you have

[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)

3 0
2 years ago
Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm
madreJ [45]

Answer:

See explanation

Step-by-step explanation:

1 step: \overline{GI}\cong \overline {JL} - given

2 step: \overline{GI}\cong \overline{GH}+\overline{HI} - Segments Addition Postulate

3 step: \overline{GH}+\overline{HI}\cong \overline {JL} - Substitution Property

4 step: \overline {JL}\cong \overline {JK}+\overline {KL} - Segments Addition Postulate

5 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {KL} - Substitution Property

6 step: \overline{GH}\cong \overline {KL} - given

7 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {GH} - Substitution Property of Equality

8 step: \overline{HI}\cong \overline {JK} - Subtraction Property of Equality

3 0
2 years ago
A toy car costing $50 is reduced by 10% in the sale. How much does it cost now? Show me your work plz
wlad13 [49]

Answer:

$45

Step-by-step explanation:

divide 50 by 100 (as in 100%) then multiply it by 90 (as in 90%)

50 ÷ 100 × 90 = 45

5 0
2 years ago
Read 2 more answers
Kona wants to bake at most 30 loaves of banana bread and nut bread for a bake sale. Each loaf of banana bread sells for $2.50,an
Mila [183]

Answer:

Step-by-step explanation:

30 loaves of banana bread and nut bread at most

Banana bread is sold for $2.5

Nut bread is sold for $2.75

Total income she wants to make $44

Given that x represent loaves of bread

And y represent loaves of nut bread

First statement

She wants to make at most 30 of both loaves bread and nut, at most means the maximum she wanted to make is 30, so it is either 30 or less than 30.

Therefore the sum of the loaves bread and the nut bread is less or equal to 30.

Mathematically,

x+y≤30. Equation 1

Second statement

She wants to make at least a gain of $44, that is, the minimum money she wants to make is $44

Banana bread is sold for $2.5

Therefore she will make 2.5x by banking x nut bread

Nut bread is sold for $2.75

She will make 2.75y by baking y nut bread.

Therefore,

Since she wants to make at least $44,

The inequality is,

2.5x+2.75y≥ 44. equation 2

The inequalities model are

1. x+y≤30

2. 2.5x+2.75y≥ 44

3 0
2 years ago
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