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2 years ago

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lucas divides his pizza into three equal pieces for himself and his two friends. his friend teddy eats 5/8 of his piece for lunc

h and a further 2/5 of what remains for dinner. what fraction of the original pizza did teddy eat for dinner

1 answer:

Marina CMI [18]2 years ago

8 0

Answer:

He ate $\frac{1}{20}$ of the original pizza for dinner

Step-by-step explanation:

- Lucas divides his pizza into three equal pieces for himself and his two

friends

∵ There are 1 pizza

∵ It is divided into 3 equal parts

∴ Each part is $\frac{1}{3}$

∴ Teddy takes $\frac{1}{3}$ of the pizza

- Teddy eats $\frac{5}{8}$ of his piece for lunch and a further $\frac{2}{5}$ of what

remains for dinner

∵ His piece is $\frac{1}{3}$

∵ He eats $\frac{5}{8}$ of his piece for lunch

∴ He eats for lunch = $\frac{5}{8}$ × $\frac{1}{3}$ = $\frac{5}{24}$

- Let us find the remaining of his piece for dinner

∵ The remaining = $\frac{1}{3}$ - $\frac{5}{24}$

- Make L.C.M for the denominators

∵ The L.C.M of 3 and 24 is 24

∵ $\frac{1}{3}$ = $\frac{1*8}{3*8}$ = $\frac{8}{24}$

∴ The remaining = $\frac{8}{24}$ - $\frac{5}{24}$

∴ The remaining = $\frac{3}{24}$ = $\frac{1}{8}$

∵ He ate $\frac{2}{5}$ of the remaining for dinner

∵ The remaining of his piece = $\frac{1}{8}$

∴ He ate for dinner ⇒ $\frac{2}{5}$ × $\frac{1}{8}$

∴ He ate for dinner ⇒ $\frac{2}{40}$ = $\frac{1}{20}$

* He ate $\frac{1}{20}$ of the original pizza for dinner

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Given: Picture of the star is made up of 4 unshaded equilateral triangles of equal area and a shaded square.

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Answer:

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Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

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As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

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Answer:

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Step-by-step explanation:

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The probability of finding a value of at lower than x is:

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$P(c \leq X \leq d) = \frac{d - c}{b - a}$

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$P(X > x) = \frac{b - x}{b - a}$

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This means that $a = 20, b = 28$

a. What’s the probability density function?

The probability density function of the uniform distribution is:

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In this question:

$f(x) = \frac{1}{28 - 20} = \frac{1}{8}$

b. What’s the probability that X will take on a value between 21 and 25?

$P(21 \leq X \leq 25) = \frac{25 - 21}{28 - 20} = \frac{4}{8} = 0.5$

0.5 = 50% probability that X will take on a value between 21 and 25.

c. What’s the probability that X will take on a value of at least 26?

$P(X > 26) = \frac{28 - 26}{28 - 20} = \frac{2}{8} = 0.25$

0.25 = 25% probability that X will take on a value of at least 26.

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