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ra1l [238]
2 years ago
4

The expression $\sqrt{(\sqrt{56})(\sqrt{126})}$ can be simplified to $a\sqrt b$, where $a$ and $b$ are integers and $b$ is not d

ivisible by any perfect square greater than 1. What is $a+b$?
Mathematics
1 answer:
Delicious77 [7]2 years ago
3 0

Answer:

  23

Step-by-step explanation:

\sqrt{\sqrt{56}\sqrt{126}}=\sqrt{\sqrt{7056}}=\sqrt{\sqrt{84^2}}\\\\=\sqrt{84}=2\sqrt{21}\\\\2+21=\bf{23}

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Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
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Answer:

B) 28.53 unit²

Step-by-step explanation:

The diagonal AD divides the quadrilateral in two triangles:

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  2. Triangle ACD

Area of Quadrilateral will be equal to the sum of Areas of both triangles.

i.e.

Area of ABCD = Area of ABD + Area of ACD

Area of Triangle ABD:

Area of a triangle is given as:

Area = \frac{1}{2} \times base \times height

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Height = AD = 8.6

Using these values, we get:

Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43

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Base = AC = 4.3

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Using the values in formula of area, we get:

Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30

Thus, Area of Triangle ACD is 16.30 square units

Area of Quadrilateral ABCD:

The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²

None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²

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Answer:

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