Question

Write a program that reads an integer value from the user representing a year. The purpose of the program is to determine if the year is a leap year (and therefore has 29 days in February) in the Gregorian calendar. A year is a leap year if it is divisible by 4, unless it is also divisible by 100 but not 400. For example, the year 2003 is not a leap year, but 2004 is. The year 1900 is not a leap year because it is divisible by 100, it is also divisible by 400. Produce an error message for any input value less than 1582 (the year the Gregorian calendar was adopted).

Answer 1

Answer:

Following program in c language:

#include <stdio.h> // header file

int main() // main method

{

   int year1 ; // varuiable declaration

   printf("Enter year: ");

   scanf("%d",&year1); // input year

   if(year1<1582) // checking condition if year less then 1582

   {

   printf(" invalid year please input correct year");

}

else

{

   if(year1 % 4 == 0) // checking condition of leap year  

   {

       if( year1 % 100 == 0) // checking condition of leap year  

       {

           if ( year1 % 400 != 0)  

               printf("%d is a Leap Year", year1);

           else

               printf("%d is not a Leap Year", year1);

       }

       else

           printf("%d is a Leap Year", year1 );

   }

   else

       printf("%d is not a Leap Year", year1);

}

   return 0;

}

Output:

First output

Enter year:  2004

2004 is a leap year

Second output

Enter year:  2003

2003 is not a leap year

Third output

Enter year:  200

invalid year please input correct year

Explanation:

In this program we input a year by user in "year1" variable .Initially check if year is less then 1582 then display message in console " invalid year please input correct year" otherwise control moves to else block and check the condition which is given below.

A year is leap year if it is satisfied these condition

(year1 % 4 == 0) and (year1 % 100 == 0) and  (year1 % 400 != 0)

Otherwise it is not a leap year.