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LUCKY_DIMON [66]
2 years ago
6

You are planning to implement dual stack of IPv4 and IPv6 in your network. Currently, your network consists of servers, routers,

and switches that have not been upgraded for several years. You are still running the Windows Server 2003. When implementing dual stack, which of the following will be your primary concerns?
Computers and Technology
1 answer:
AleksandrR [38]2 years ago
4 0

Answer:

Ensuring that Internet Service Providers (ISPs) work with IPv6 .

Explanation:

An Internet Service Provider (ISP), it is the company that supply to other companies or an individuals for accessing the Internet and some other services such as virtual hosting and Web site building. ISP has the telecommunication line and an equipment to access the required point of area for the Internet.

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python Write a class named Taxicab that has three **private** data members: one that holds the current x-coordinate, one that ho
Blizzard [7]

Answer:

see explaination

Explanation:

class Taxicab():

def __init__(self, x, y):

self.x_coordinate = x

self.y_coordinate = y

self.odometer = 0

def get_x_coord(self):

return self.x_coordinate

def get_y_coord(self):

return self.y_coordinate

def get_odometer(self):

return self.odometer

def move_x(self, distance):

self.x_coordinate += distance

# add the absolute distance to odometer

self.odometer += abs(distance)

def move_y(self, distance):

self.y_coordinate += distance

# add the absolute distance to odometer

self.odometer += abs(distance)

cab = Taxicab(5,-8)

cab.move_x(3)

cab.move_y(-4)

cab.move_x(-1)

print(cab.odometer) # will print 8 3+4+1 = 8

5 0
2 years ago
Create the class named SortFile. The class will have a single attribute, which is an ArrayList of integers. The class will have
S_A_V [24]

Answer:

See explaination

Explanation:

//SortFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

public class SortFile {

// array list of integers to store the numbers

private ArrayList<Integer> list;

// default constructor

public SortFile() {

// initializing list

list = new ArrayList<Integer>();

// reading file name using a scanner

Scanner sc = new Scanner(System.in);

System.out.print("Enter file name: ");

String filename = sc.nextLine();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

// opening file

sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

// closing file

sc.close();

} catch (FileNotFoundException e) {

// exception occurred.

System.err.println(e);

}

}

// constructor taking a file name

public SortFile(String filename) {

// initializing list

list = new ArrayList<Integer>();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

Scanner sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

sc.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

}

// method to return a sorted array of integers containing unique elements

// from list

public int[] sort() {

// creating an array of list.size() size

int arr[] = new int[list.size()];

// count of unique (non duplicate) numbers

int count = 0;

// looping through the list

for (int i = 0; i < list.size(); i++) {

// fetching element

int element = list.get(i);

// if this element does not appear before on list, adding to arr at

// index=count and incrementing count

if (!list.subList(0, i).contains(element)) {

arr[count++] = element;

}

}

// now reducing the size of arr to count, so that there are no blank

// locations

arr = Arrays.copyOf(arr, count);

// using selection sort algorithm to sort the array

int index = 0;

// loops until index is equal to the array length. i.e the whole array

// is sorted

while (index < arr.length) {

// finding the index of biggest element in unsorted array

// initially assuming index as the index of biggest element

int index_max = index;

// looping through the unsorted part of array

for (int i = index + 1; i < arr.length; i++) {

// if current element is bigger than element at index_max,

// updating index_max

if (arr[i] > arr[index_max]) {

index_max = i;

}

}

// now we simply swap elements at index_max and index

int temp = arr[index_max];

arr[index_max] = arr[index];

arr[index] = temp;

// updating index

index++;

// now elements from 0 to index-1 are sorted. this will continue

// until whole array is sorted

}

//returning sorted array

return arr;

}

//code for test-run

public static void main(String[] args) {

//initializing SortFile using default constructor

SortFile sortFile = new SortFile();

//displaying sorted array

System.out.println(Arrays.toString(sortFile.sort()));

}

6 0
2 years ago
Using the College Registration example from Section 6.7.3 as a starting point, do the following:
Margarita [4]

Answer:

Check the explanation

Explanation:

INCLUDE Irvine32.inc

TRUE = 1

FALSE = 0

.data

gradeAverage WORD ?

credits WORD ?

oKToRegister BYTE ?

str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0

main PROC

call CheckRegs

exit

main ENDP

CheckRegs PROC

push edx

mov OkToRegister,FALSE

; Check credits for valid range 1-30

cmp credits,1 ; credits < 1?

jb E1

cmp credits,30 ; credits > 30?

ja E1

jmp L1 ; credits are ok

; Display error message: credits out of range

E1:

mov edx,OFFSET str1

call WriteString

jmp L4

L1:

cmp gradeAverage,350 ; if gradeAverage > 350

jna L2

mov OkToRegister,TRUE ; OkToRegister = TRUE

jmp L4

L2:

cmp gradeAverage,250 ; elseif gradeAverage > 250

jna L3

cmp credits,16 ; && credits <= 16

jnbe L3

mov OkToRegister,TRUE ; OKToRegister = TRUE

jmp L4

L3:

cmp credits,12 ; elseif credits <= 12

ja L4

mov OkToRegister,TRUE ; OKToRegister = TRUE

L4:

pop edx ; endif

ret

CheckRegs ENDP

END main

4 0
2 years ago
Besides technical skill, what is the most important factor for staying employed and being offered promotions?
slavikrds [6]
C. showing professional behavior 
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solniwko [45]
Abstraction comes from two latin words; abs which means away and trahere which mean to draw. From the meaning itself, it is to draw away something from specific objects, individuals, group, etc. In the computer world, a programmer hides all relevant data pertaining to the relevance of a data. It is done to increase efficiency and and reduce complexity. 
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2 years ago
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