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Vsevolod [243]
2 years ago
13

MODELING REAL LIFE In 60 seconds, a car in a parade travels 0.2 mile. The car traveled the last 0.05 mile in 12 seconds. How lon

g did it take for the car to travel 0.1 mile?
Mathematics
2 answers:
schepotkina [342]2 years ago
8 0
Well, if we put everything together we have gone .25 of a mile in 72 seconds.

Since .25 is a quarter of a mile (1/4) we can estimate that in 288 seconds the car has traveled one mile. We got 288 by multiplying .25 by 4.
antiseptic1488 [7]2 years ago
4 0

Answer:

First 0.1 miles: 32 seconds

Last 0.1 miles: 28 seconds

Step-by-step explanation:

The car traveled 0.2 mile in 60 seconds.

The last 0.05 miles were done in 12 seconds.

Then the first 0.2 - 0.05 = 0.15 miles were done in 60 - 12 =  48 seconds. The speed of the car was: 0.15/48 = 0.003125 mi/s

At this speed it takes 0.1/0.003125 = 32 s to travel the first 0.1 mile.

In the second 0.1 mile, 0.05 miles are done at the same speed than before. It takes 0.05/0.003125 = 16 s, the next 0.05 miles were traveled in 12 seconds,  making a total of 16+12 = 28 seconds

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Find the area of segment CFD given the following information: radius = 8in, area of ΔCBD = 25.9in2, and m∠CBD = 54° Round your a
Llana [10]

Answer:

A. 4.26 in^2

Step-by-step explanation:

Step 1: Find the area of the sector DBC. Here we have to use the formula.

Area of a sector = Central Angle/360 *πr^{2}

The area of the sector DBC = (54/360)*3.14*8^{2}

= 30.16

Step 2: Area of segment CFD = Area of the sector DBC - Area of the ΔCBD

= 30.17 - 25.9

Area of segment CFD = 4.27in^2

8 0
2 years ago
Kristen owns 61 shares of Prince Waste Collection and 45 shares of Nar Heating/Cooling. Nar Heating/Cooling is worth $7.88 per s
skelet666 [1.2K]
Given:
Kristen owns 61 shares of Prince Waste Collection
Kristen owns 45 shares of Nar Heating/Cooling

                        Number of Shares      Value per share          Total
Prince Waste
Collection                  61                             16.59                   1,011.99
Nar Heating/
Cooling                     45                              7.88                       354.60
Total                        106                                                         1,366.59

If Kristen sells all of her stocks, she will receive a total of $1,366.59
6 0
2 years ago
Read 2 more answers
In the following diagram \overline{DE} \parallel \overline{FG}
Gnesinka [82]

Answer:

<x = 31°

Step-by-step explanation:

m<BCA = m<GCJ (vertical angles)

m<BCA = 59° (substitution)

Since line KL is perpendicular to line FG, the angle formed at point B is 90°.

Therefore, m<ABC = 90°

m<BAC + m<ABC + m<BCA = 180° (sum of triangle)

m<BAC + 90° + 59° = 180° (Substitution)

m<BAC + 149° = 180°

m<BAC = 180° - 149°

m<BAC = 31°

<x = <BAC (vertical angles)

m<x = 31° (substitution)

7 0
2 years ago
Jeff earned his pilot's license and flew to visit his brother 200 miles away. A headwind of 20 mph slowed down the plane's speed
lora16 [44]
<h2>Plane's speed without wind i s 117.68 mph</h2>

Step-by-step explanation:

We have speed of plane without wind is x.

Distance to brothers place = 200 miles.

A headwind of 20 mph slowed down the plane's speed on the first leg of the trip

Speed to brothers place = x - 20

We have

         Distance = Speed x Time

         200=(x-20)\times t_1\\\\t_1=\frac{200}{x-20}

A tailwind of 20 mph sped up the plane on the return trip

Speed of return trip = x + 20

We have

         Distance = Speed x Time

         200=(x+20)\times t_2\\\\t_2=\frac{200}{x+20}

The entire trip took 3.5 hours.

That is

            t_1+t_2=3.5\\\\\frac{200}{x-20}+\frac{200}{x+20}=3.5\\\\200x+4000+2000x-4000=3.5(x-20)(x+20)\\\\400x=3.5x^2-1400\\\\7x^2-800x-2800=0\\\\\texttt{x = 117.68mph or x =-3.40mph}

Plane's speed without wind i s 117.68 mph

7 0
2 years ago
Miss Croft made snack bags for the picnic that contain three types of snacks: packages of crackers, packages of cookies, and can
jek_recluse [69]

Answer: $1.25

Step-by-step explanation:

Let the cost of cracker be a.

Let the cost of cookies be b.

Let the cost of candy bars be c.

From the question,

6a + 6b + 6c = $21

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

To solve this, we first pick any two pairs of equation. This will be:

6a + 6b + 6c = $21 ....... i

8a + 5b + 10c = $26 ....... ii

Multiply equation i by 8

Multiply equation ii by 6

48a + 48b + 48c = $168 ....... iii

48a + 30b + 60c = $156 ....... iv

Subtract equation iv from iii

18b - 12c = 12

We then pick another two pairs

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

Multiply equation i by 5

Multiply equation ii by 8

40a + 25b + 50c = $130

40a + 32b + 56c = $148

Subtract the equations

-7b - 6c = -18

Then, solve the new equations formed

18b - 12c = 12 ....... v

-7b - 6c = -18 ....... vi

Multiply equation i by -7

Multiply equation ii by 18

-126b + 84c = -84

-126b - 108c = -324

Subtract the equations

192c = 240

c = 240/129

c = $1.25

From equation v, put the value of c

18b - 12c = 12

18b - 12($1.25) = 12

18b - $15 = $12

18b = $27

b = $27/18

b = $1.5

Since,

6a + 6b + 6c = $21

6a + 6($1.5) + 6($1.25) = $21

6a + $9 + $7.5 = $21

6a + $16.5 = $21

6a = $21 - $16.5

6a = $4.5

a = $4.5/6

a = $0.75

One candy bar cost $1.25

6 0
2 years ago
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