Answer:
Option (D)
Step-by-step explanation:
Given polynomial is,
2x³ - 3x² - 3x + 2
If (x - 2) is the factor of the given polynomial,
By synthetic division we can get the other factor.
2 | 2 -3 -3 2
<u> 4 2 -2 </u>
2 1 -1 0
Therefore, other factor of the given polynomial is (2x² + x - 1)
Now (2x² + x - 1) = 2x² + 2x - x - 1
= 2x(x + 1) -1(x + 1)
= (2x - 1)(x + 1)
Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)
Option (D) will be the answer.
In this question , it is given that p represents cost of 1 container of popcorn . Therefore cost of 5 containers of popcorn = 5p and cost of 3 containers of popcorn = 3p .
And g represents cost of 1 container of granola bars. THerefore cost of 4 containers of granola bars = 4g and cost of 6 containers of granola bars = 6g .
According to the given question, the required linear equations are
5p+4g=42.50 , 3p+6g =34.50 .
And these are the the required system of linear equation .
Answer:
Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)
Step-by-step explanation:
Given: Probability of a children under age 5 has food allergies = 7%
=
To find : Probability of atleast one of 12 student has food allergies
Probability of a chindren under age 5 does not have food allergies = 
⇒ prob = 
now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.
But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)
Probability of 0 student having allergy out of 12 student = 
Therefore, Probability of atleast one of 12 student has food allergies
= 
= 
≈ 0.58 ( approx)
1:4
when sugar=34
times 34 both sides
34*4=136
1:4=34:136
should use 136 cups of water
that is alot of water
that's a big feeder (8.5 gallons. the water alone weighs about 74.8lb)
should use 136 cups (wow)
Answer:
The value of P(z<1.00)=0.8413
Step-by-step explanation:
Using a standard normal table, the area under the standard normal curve below the given value of z=1 is:
z <u> .00</u> .01
0.9 0.81594 0.81859
<u>1.0</u> <u>0.84134</u> 0.84375
1.1 0.86433 0.86650
P(z<1.00)=0.84134
Rounded to 4 decimal paces
P(z<1.00)=0.8413
