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choli [55]
2 years ago
3

The city council conducts a survey of the city's residents to determine which services are most used by the community. 60% of th

e residents say that they use the library, and 35% of the residents say they use the library and the recycling center. What is the probability that a resident uses the recycling center given that they use the library? Express your answer as a fraction in simplest form.
Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
3 0

Answer: \dfrac{7}{12}

Step-by-step explanation:

Let A denotes the event of residents say that they use the library.

B denotes the event that residents say that they uses the recycling center.

As per given , we have

P(A)=0.60

P(A∩B)=0.35

Using conditional probability formula we have,

P(B|A)=\dfrac{P(A\cap B)}{P(A)}

i.e. The probability that a resident uses the recycling center given that they use the library =\dfrac{0.35}{0.60}=\dfrac{35}{60}=\dfrac{7}{12}

Hence, the required probability = \dfrac{7}{12}

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For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.
luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA)  and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

m\angle COB=arc\ CD ----> by central angle

we have

arc\ CD=125^o

therefore

m\angle COB=125^o

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

m\angle BCA+m\angle\ ABC=90^o ---> by complementary angles in a right triangle

we have

m\angle ABC=55^o

substitute

m\angle BCA+55^o=90^o

m\angle BCA=90^o-55^o=35^o\\

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

m\angle CBO+m\angle COB+m\angle BCO=180^o ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

m\angle COB=125^o

m\angle BCO=m\angle BCA=35^o -----> have measure equal to 35 degrees

substitute

m\angle CBO+125^o+35^o=180^o

m\angle CBO=180^o-160^o=20^o

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

m\angle ABC=m\angle CBO+m\angle ABO ----> by angle addition postulate

we have

m\angle ABC=55^o

m\angle CBO=20^o

substitute

55^o=20^o+m\angle ABO

m\angle ABO=55^o-20^o=35^o ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

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