<span>Using the information we have
3x+4=40
Do the same to each side of the equation to eliminate for x.
3x+4=40 Minus 4 from each side
3x=40-4
3x=36
Divide 3 from each side
x=36/3
x=12
AC=3x+4
insert the value of x
3(12)+4=40
AC=40
AD=20</span>
The quantities in the proportion you give add to 16 pounds, of which 2 pounds are cement. That is, cement constitutes 1/8 of the total weight.
For each yard of concrete, 4000 lb/8 = 500 lb of cement are used.
For 12.5 yards of concrete, 12.5 * 500 = 6,250 pounds of cement will be used.
_____
"yard" in this case is shorthand for "cubic yard".
<span>we have to solve simultaneous equations.
x = 10 oz. boxes
y = 16 oz. boxes
simultaneous equations
x + y = 24 ---1)
3.50x + 5.00y = 97.50 ----2)
to solve for x we need to eliminate y, therefore we have to multiply 1st equation by 5
5x + 5y = 120 --3)
subtract 3) - 2)
5x - 3.50x = 120 - 97.50
1.50x = 22.5 x = 15
number of 10 oz. boxes are 15. answer is d.15</span>
To expand (3 - 2x)^6 use the binomial theorem:
(x + y)^ n = C(n,0) x^ny^0 + C(n,1)x^(n-1) y + C(n,2)x^(n-2) y^2 + ...+ C(n,n+1)xy^(n-1) + C(n,n)x^0y^n
So, for x = 3, y = -2x , and n = 6 you get:
(3 - 2x) ^6 = C(6,0)(3)^6 + C(6,1)(3)^5 (-2x) + C(6,2) (3)^4 (-2x)^3 + C(6,3) (3^3) (-2x)^4 + C(6,4)(3)^2 (-2x)^4 + C(6,5) (3) (-2x)^5 + C(6,6) (-2x)^6
So, the sixth term is C(6,5)(3)(-2x)^5 = 6! / [5! (6-5)! ] * 3 * (-2)^5 x^5 = - 6*3*32 = - 576 x^5.
The coefficient of that term is - 576.
Answer: - 576
Answer:
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Step-by-step explanation:
while solving this sum the main steps are...
make sure
area of 1st triangle =area of the new....tria..
