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Morgarella [4.7K]
2 years ago
3

Which of the following statements describes a potential problem associated with indirect headlines in print ads? Multiple Choice

They generate curiosity in readers, which takes attention away from the message. They may not be provocative enough to direct a reader's attention to the rest of the message. They avoid the use of questions or provocations. They avoid the use of how-to statements. They are often treated as subheads.
Engineering
1 answer:
inessss [21]2 years ago
8 0

Answer:

They may not be provocative enough to direct a reader's attention to the rest of the message

Explanation:

Indirect headlines ads:

 When the viewers and readers reads a certain indirect headlines, they are curious to know more about the situation and a sense of curiosity arises in their minds. But the answers to their questions or inquiries lies in the body of the advertisement itself.

Answer-They may not be provocative enough to direct a reader's attention to the rest of the message

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A horizontal pipe has an abrupt expansion from D1 5 8 cm to D2 5 16 cm. The water velocity in the smaller section is 10 m/s and
anyanavicka [17]
  • Answer:  Explanation:  Application of the bernoulli's equation comes in from conservation of mass flow.  The cross sectional area of the two pipes are calculated. from A = πD²/4 The velocity of water from conservation of mass flow is also calculated ; V2 = Ac1V1/Ac2 The Loss coefficient is then calculated from KL = (1 - Ac1²/Ac2²)² Then the head Loss (hL) is calculated  The detailed calculated and appropriate steps is as shown in the attached files.

5 0
2 years ago
A binary star system consists of two stars of masses m1m1m_1 and m2m2m_2. The stars, which gravitationally attract each other, r
d1i1m1o1n [39]

Answer:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

Explanation:

The question is: <em>Find the magnitude of the centripetal acceleration of the star with mass m₂</em>

The <em>centripetal acceleration</em> is the quotient of the centripetal force and the mass.

                a_c=\dfrac{F_c}{m}

Thus, you can write the equations for each star:

     

       a_c_1=\dfrac{F_c_1}{m_1}

       a_c_2=\dfrac{F_c_2}{m_2}

As per Newton's third law, the centripetal forces are equal in magnitude. Then:

       a_c_1\times m_1=a_c_2\times m_2

Now you can clear a_c_2:

          a_c_2=\dfrac{a_c_1\times m_1}{m_2}

6 0
2 years ago
2. A ¼ in. diameter rod must be machined on a lathe to a smaller diameter for use as a specimen in a tension test. The rod mater
gladu [14]

Answer:

we use

sigma=force /area\\A=\pi r^2\\D=2*r

5 0
2 years ago
1. Add:<br>(i) 5xy, -2xy, -11xy, 8xy<br>(iv) 3a - 2b + c, 5a + 8b -70​
Cerrena [4.2K]

Answer:

(i) 0

(iv) 8a+6b+c-70

Explanation:

Hope this helps you

8 0
1 year ago
what is the advantage of decreasing the field current of a separately excited dc motor below its nominal value
enyata [817]

Answer:

Ability to rotate at higher speeds

Explanation:

Constant K1 becomes greater than the other constant K2

This translates to that the motor being able to rotate at high speeds, without necessarily exceeding the nominal armature voltage.

The armature voltage is the voltage that is developed around the terminals of the armature winding of an Alternating Current, i.e AC or a Direct Current, i.e DC machine during the period in which it tries to generate power.

6 0
2 years ago
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