Let x represent the number of type A table and y represent the number of type B tables.
Minimize: C = 265x + 100y
Subject to: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1
From, the graph the corner points are (20, 20), (39, 1), (30, 1)
For (20, 20): C = 265(20) + 100(20) = $7,300
For (39, 1): C = 265(39) + 100 = $10,435
For (30, 1): C = 265(30) + 100 = $8,050
Therefore, for minimum cost, 20 of type A and 20 of type B should be ordered.
Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
Answer:
0.24 and 1.32
Step-by-step explanation:
you divide 2.28 by 9.5 for the first answer then multiply that answer by 5.5
20 crunchy munchy=2.50 this means 2.50/20=0.125 cents per candy (i assume is candy)
40 crunchy munchy=4.00 4/40=0.100 cents per candy - this is cheaper than previous one
1 quart of milk =1.50 dollars
you cant actuality compare candy to milk