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2 years ago

If the expression 2x/a plus b = c is solved for x in terms of a, b, and c, then x = what?

Mathematics

1 answer:

Doss [256]2 years ago

3 0

Answer:

The value of x in terms of a, b ans c is $x=\frac{ac-ab}{2}$

Step-by-step explanation:

We have given the expression $\frac{2x}{a}+b=c$

We have to find the value of x in terms of a, b and c

So $\frac{2x}{a}+b=c$

$\frac{2x}{a}=c-b$

$2x=a(c-b)$

$2x=ac-ab$

$x=\frac{ac-ab}{2}$

So the value of x in terms a ,b and c is $x=\frac{ac-ab}{2}$

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Computing if a computer can do one calculation in 0.0000000015 second, then the function t(n) = 0.0000000015n gives the time req

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2 years ago

A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting

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Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees} = \frac{6}{15}$

b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.

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= $\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}$

= $\frac{\frac{5}{15} \times \frac{6}{14}}{\frac{5}{15} } = \frac{6}{14}$ .

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c.) The probability that a consultant wins on the first draw =

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d.) The probability of two secretaries winning both tickets

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= $\frac{6}{15} \times \frac{5}{14} = \frac{1}{7}$

Therefore the only statement that is not true is b.)

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