Question

In the graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded and labeled B, and the area where f(x) and g(x) have shading in common is labeled AB. Graph of two intersecting lines. One line g of x is solid and goes through the points negative 3, 0, negative 4, negative 1 and is shaded in below the line. The other line f of x is solid, and goes through the points 1, 1, 2, negative 1 and is shaded in below the line. The graph represents which system of inequalities? y ≤ −2x + 3 y ≤ x + 3 y ≥ −2x + 3 y ≥ x + 3 y ≤ −3x + 2 y ≤ −x + 2 y > −2x + 3 y > x + 3

Answer 1

Answer:

First option:  $\left \{ {{y\leq -2x + 3} \atop {y \leq x + 3}} \right.$

Step-by-step explanation:

The missing graph is attached.

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and  "b" is the y-intercept.

We can observe that:

1. Both lines have the same y-intercept:

$b=3$

2. The lines are solid, then the symbol of the inequality must be $\leq$ or $\geq$.

3. Since both shaded regions are below the solid lines, the symbol is:

$\leq$

Based on this and looking at the options given, we can conclude that the graph represents the following system of inequalities:

$\left \{ {{y\leq -2x + 3} \atop {y \leq x + 3}} \right.$

Answer 2

Answer:

y ≤ −2x + 3

y ≤ x + 3

Step-by-step explanation:

they both share the slope of 3.

line a has a slope of -2

line b has a slope of 1

the sign ≤ means that the inequalities have a solid line and there below the line.