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Contact [7]
2 years ago
5

Why did the paper rip when the student tried to stretch out the horizontal axis of his graph? Unscramble this letters to figure

it out: T, N, S, O, I, E, N, X
Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0
Tension seems the obvious answer here, but then we are left with x. Since the horisontal line on a graph is 'x'. The answer appears to be Tension X (Tension on X axis. Hope this helps.
Anna35 [415]2 years ago
3 0

Answer:

The force applied by student is greater than tension then the paper rip.

So word fitted is Tension.

Step-by-step explanation:

Given the letters  T, N, S, O, I, E, N, X                                                       we have to Unscramble these letters so that the word formed is fitted with the reason why the paper rip when the student tried to stretch out the horizontal axis of his graph.

The word which is fitted is tension and this is the reason of above.

Tension is a type of force act in opposite direction of motion and this is equal to weight. If the amount of force involved is too greater than tension then it breaks. Like in above the force applied by student is greater than tension then the paper rip.

So word fitted is Tension.

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A theatre has the capacity to seat people across two levels, the Circle and
andriy [413]

Answer: 76.19\%

Step-by-step explanation:

<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and \frac{2}{3} of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is 2:5.

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

\frac{2}{5}=\frac{528}{s}

Solving for "s", we get:

s*\frac{2}{5}=528\\\\s=528*\frac{5}{2}\\\\s=1,320

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

Total=1,320\ seats+528\ seats=1,848\ seats

 We know that \frac{2}{3} of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

(1,320)(\frac{2}{3})=880

Therefore, the total number of seats that were occupied las Friday is:

Total\ occupied=880\ seats+528\ seats=1,408\ seats

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

\frac{100}{1,848}=\frac{p}{1,408}

Solving for "p", we get:

(1,408)(\frac{100}{1,848})=p\\\\p=76.19\%

8 0
2 years ago
Aluminium coated dewars are cylindrical flasks used to safely store and transport liquid nitrogen, dry ice etc. A company manufa
Nitella [24]

This question is Incomplete because it lacks the diagram showing the containers as well as the required options. Find attached to this answer the appropriate diagram.

Complete Question

Aluminium coated dewars are cylindrical flasks used to safely store and transport liquid nitrogen, dry ice etc. A company manufactures such dewars of different sizes. Shown here are two dewars, both of the same height but of different diameters. How much aluminium will be required to cover Dewar A compared to that required for Dewar B? (Note: The base and the lid are NOT made up of aluminium.)

A) 1/3 times

B) 3 times

C) 9 times

D) The same amount of aluminum will be required.

Answer:

B) 3 times

Step-by-step explanation:

From the question, we are told that we are to find the amount of aluminum to cover Dewar A and B , we are also told that the base and the lid are not covered with aluminum.

From this information, we can determine that we are to find the curved or Lateral surface area of the cylinder because the base and lid are not included

The curved surface area of a cylinder is calculated as 2πrh

We told that both cylinders have the same height. Hence,

For Dewar A

We have Diameter of 30 cm, radius = Diameter ÷ 2 = 30cm ÷ 2 = 15cm.

Height = h

The curved surface area = 2πrh

= 2 × π × 15 ×h

= 30πhcm²

For Dewar B

We have Diameter of 10 cm, radius = Diameter ÷ 2 = 10cm ÷ 2 = 5cm.

Height = h

The curved surface area = 2πrh

= 2 × π × 5 ×h

= 10πhcm²

When we compare the curved surface Dewar A to the curved surface area of Dewar B

Dewar A : Dewar B

30πhcm² : 10πhcm²

3(10πhcm²) : 10πhcm²

From the above comparison, we can see that 3 times more aluminum is required to cover Dewar A compared to Dewar B.

6 0
2 years ago
In the figure, angle ZYX is measured in degrees. The area of the shaded sector can be determined using the formula StartFraction
tensa zangetsu [6.8K]

<u>The given options are:</u>

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.

(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.

(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.

Answer:

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

Step-by-step explanation:

The area of the shaded sector can be determined using the formula:

\frac{m\angle ZYX}{360^\circ} \cdot \pi r^2

m\angle XYZ=$Central angle of XYZ\\\pi r^2$=Area of a Circle

360^\circ =$Total Angle

Therefore, the formula is:

\dfrac{m\angle ZYX}{360^\circ} \cdot \pi r^2\\\text{Area of XYZ}=\dfrac{\text{Cental Angle of XYZ}}{\text{Total Angle}} X \text{Area of the Circle}

Therefore, the formula is best explained by Option A.

7 0
2 years ago
A group of friends are going ice skating. The price of admission is $3.25. As a group, they spent $14 on refreshments. If they s
Helen [10]
Start with $30.25. 
Subtract $14.00 to isolate the amount of money spent on admission. 
30.25-14.00= 16.25. As a group $16.25 was spent on admission.
Admission is 3.25 per person. Divide 16.25 by 3.25. 
16.25/3.25=5. 
5 friends went ice skating. 
4 0
2 years ago
Read 2 more answers
Is 12x=7y-10y a linear equation?
Kruka [31]
 <span>12x = 7y-10y 
12x = -3y 
-4x= y 
y = -4x</span>
4 0
2 years ago
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