Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
His annual salary as a pharmacist is $51,200
There are a total of 52 weeks in an year.
(a) Weekly salary = annual salary/ number of weeks = 51,200/52 = $984.62 (rounded to the nearest cent)
Howard's weekly salary to the nearest cent = $984.62
(b) His salary in first three weeks = 984.62*3 = $2,953.85
Howard's earnings during the first three weeks to the nearest cent = $2,953.85
(c) He has to pay the agency 40% of his three week salary which is = 0.4*2953.85 =1,181.54
Howard must pay to the employment agency to the nearest dollar = $1,182
Answer:
<u>The area of the hexagon is A. 96√3 cm²</u>
Step-by-step explanation:
Let's recall the formula of the area of an hexagon, this way:
Area = (3√3/2) * s²
Area = (3√3/2) * 8²
Area = (3√3/2) * 64
Area = 192√3/2
Area = 96√3 cm²
<u>The area of the hexagon is A. 96√3 cm²</u>
Hello!!
It will be the same since there is no common factor. You just need to arrange in order.
6x^2 + 72xy - 12x + 81y^2 + 27y
Good luck :)
I feel like the answer is
10h = 110
although it's so simple that I'm not even sure it would be considered an equation.
I got the answer because she works, in total, 10 hours a week. She makes $130 a week, but since $20 comes from the dog walking, you have to do 130 minus 20 which is 110. That's what I did anyway.
