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Alex
2 years ago
9

Jenny paid $8.54 for pizza.she now has $16.79.with how much money did she start

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
6 0

Answer:

she started with $25.33

Step-by-step explanation:

$8+$16= $24

54 cents + 79 cents= $1.33

$24+$1.33= $25.33

otez555 [7]2 years ago
4 0

Answer:

$25.33

Step-by step explanation:

In the start she had $8.54 + $16.79= $25.33

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Which of the following could be the equation for a parabola that opens to the left with vertex (-17,2)?
Sholpan [36]
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2 years ago
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A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400
KiRa [710]

Answer:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=400, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=400*0.2=80 \geq 10

n(1-p)=400*(1-0.2)=320 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=400*0.2=80

\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8

So then we can approximate the random variable as X \sim N(\mu = 80, \sigma = 8)

And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

8 0
2 years ago
How many leap years occur between the<br> years 1700 and 1875?
Zina [86]

Step-by-step explanation:

A leap year occurs every 4th year.

So, 1875 - 1700 = 175

Now let us divide 175 by 4

175 \div 4 = 43.75 \\  here \: 43 \: represents \: the \: number \: of \:  \\ leap \: years.

So, 43 leap years occur between the years 1700 and 1875.

6 0
2 years ago
The winners of a carnival game draw a ticket from a box to determine their prize. Each winner draws a ticket and places it back
swat32

Answer:

He generates a random whole number from 1 to 3.

Step-by-step explanation:

Each winner has 3 possibilities, gets cotton candy, gets a shirt, or gets a keychain. We can asign each of this possibiltiies a number, 1 for cotton candy, 2 for the shirt and 3 for a keychain. So, for a simulation, its enough to take one of this whole numbers for each winner.

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lbvjy [14]

First of all, a bit of theory: since the area of a square is given by

A = s^2

where s is the length of the square. So, if we invert this function we have

s = \sqrt{A}.

Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

d = \sqrt{s^2+s^2} = \sqrt{2s^2} = s\sqrt{2}

So, the diagonal is the side length, multiplied by the square root of 2.

With that being said, your function could be something like this:

double diagonalFromArea(double area) {

double side = Math.sqrt(area);

double diagonal = side * Math.sqrt(2);

return diagonal;

}

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2 years ago
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