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Sergio [31]
2 years ago
13

In tissues deriving energy anaerobically (such as rapidly exercising skeletal muscle), lactate, rather than pyruvate, serves as

the end product of glycolysis.
Which of the following statements best explains why pyruvate is converted to lactate under these circumstances?
A. The mitochondrion is more permeable to lactate than to pyruvate.
B. Lactate, but not pyruvate, serves as a substrate for gluconeogenesis.
C. The conversion of pyruvate to lactate is accompanied by the production of ATP.
D. NAD+ necessary for the glyceraldehyde phosphate dehydrogenase reaction is regenerated
Biology
1 answer:
Damm [24]2 years ago
3 0

Answer: Option D

pyruvate is converted to lactate when NAD+ necessary for glyceraldehyde phosphate dehydrogenase reaction is regenerated in glycolysis.

Explanation:

Anaerobic glycolysis is the conversion of glucose to lactate in muscles cells when there is limited supply of oxygen.

When there is not enough oxygen in the muscle cells for oxidation of pyruvate to NADH(nicotinamide adenine dinuleotide hydrogen) produced in glycolysis, NAD+ (nicotinamide adenine dinucleotide) which is important for glyceraldehyde phosphate dehydrogenase is regenerated from NADH by reduction of pyruvate to lactate.

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A large agricultural chemical company is testing a new experimental pesticide. An unfortunate side effect in plants treated with
Vsevolod [243]

Answer:

The correct answer is a increase in 3-phosphoglycerate levels and a decrease in RUBP levels.

Explanation:

NADPH is a reducing equivalent that is produced during light reaction of photosynthesis.The NADPH that is produced during light react is utilized in the dark reaction.

  A decrease NADPH formation in the chroloplast will in turn decrease the formation of PGALD from phosphoglyceric acid(PGA).Some PGALD are used in the regeneration of ribulose bis phosphate(RUBP).

  From this point of view it can be stated that decrease in NADPH level decreases PGALD level which in turn decreases RUBP levels.

  As NADPH production is decreased in the chloroplast more phophoglyceric acid or 3-phosphoglycerate will accumulate thus the cellular level of PGA is increased.

   

3 0
2 years ago
Match each component of biodiversity to the example of how it contributes to ecosystem stability.
professor190 [17]

Answer:  

Genetic diversity: Some individuals in a population of wild rabbits are resistant to a new disease.

Ecosystem diversity: If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks.  

Species diversity:  Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation.  

Biodiversity of an ecosystem is usually explored by three diversities which are responsible for ecosystem stability they are : genetic diversity, ecosystem diversity and species diversity.

Genetic diversity is the variety of genes within a population of species. Each species consists of individuals bearing different genetic composition. Some individuals in a population of wild rabbits are resistant to a new disease because they exhibit genetic diversity within the population as a consequence some individuals exhibit genes which protect them against new disease.

Species diversity is the variety of species within an ecosystem. Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation is an example of species diversity. The wild rabbits from a forest and a neighboring meadow are two species living in an ecosystem stating the diversity of species in an ecosystem.

Ecosystem diversity is the variety of ecosystems in a given region.If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks is an example of ecosystem diversity because in an ecosystem there is interaction of organisms as predator prey relationship. This example is also relating with predator prey relationships in an ecosystem.


8 0
2 years ago
Read 2 more answers
A bacterial strain can grow on rich medium (which contains all the amino acids, vitamins, and a variety of carbon sources) but n
Anastasy [175]

Answer:

The correct answer is option C. "arg+leu– or arg–leu+".

Explanation:

This bacteria is not able to growth on minimal medium or minimal medium  supplemented with leucine. This means that the bacteria needs external supplementation of amino acids to growth, either arginine or leucine. Therefore, this bacteria can have the genotypes of arg+leu– or arg–leu+, meaning that the bacteria is able to synthesize either of two amino acids, but not both, because if that was the case the bacteria would be able to growth on minimal medium.

3 0
2 years ago
In mammoths, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-woo
lisabon 2012 [21]

Answer:

Genotypic and Phenotypic ratios → 1:1:1:1

  • 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair, SsWw
  • 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair, Ssww
  • 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair, ssWw
  • 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair, ssww

Explanation:

<u>Available data</u>:

  • spotted skin (S) is dominant over non-spotted skin (s)
  • wooly hair (W) is dominant over non-wooly hair (w)
  • Cross: heterozygous spotted, non-wooly mammoth with a heterozygous wooly-haired, non-spotted mammoth.

Parentals) Ssww   x   ssWw

Gametes) Sw, Sw, sw, sw

                 sW, sW, sw, sw

Punnett square)     Sw            Sw           sw           sw

                  sW      SsWw      SsWw      ssWw     ssWw

                  sW      SsWw      SsWw      ssWw     ssWw

                  sw      Ssww       Ssww       ssww      ssww

                  sw      Ssww       Ssww       ssww      ssww

F1) 4/16 = 1/4 = 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair.

Genotypic and Phenotypic ratios → 1:1:1:1

7 0
2 years ago
Which nitrogen base sequence is the partner of T-C-A-G-C-A?
Lostsunrise [7]
A-G-T-C-G-T or in other words the answer is C
4 0
2 years ago
Read 2 more answers
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