Answer:
812.40 units
Explanation:
Given that,
Annual holding cost percentage = 20%
Ordering cost = $110 per order
Annual demand = 15,000 units
Units Ordered - Price Per Unit
1-250 - $30.00
251-500 - $28.00
501-750 - $26.00
751 and up - $25.00
Optimal order quantity:
= 
= 
= 
= 812.40
Therefore, the optimal order quantity is 812.40 units.
Answer:
Objective function:
Maximize Z: 30P1 + 25P2 + 28P3
Subject to: 2.00P1 + 1.50P2 + 3.00P3 ≤ 450 (Department A constraint)
2.50P1 + 2.00P2 + P3 ≤ 350 (Department B constraint)
0.25P1 + 0.25P2 + 0.25P3 ≤ 50 (Department C constraint)
P1, P2, P3 ≥ 0 (Non-negativity)
Explanation:
The objective function is formulated from the contribution margin of the three products. For instance, the contribution of Product 1 is $30, the contribution of Product 2 is $25 and the contribution of Product 3 is $28. Thus, the objective function will be 30P1 + 25P2 + 28P3.
The constraints were obtained from the departmental labour hours requirements for each product. For instance, Product 1 requires 2 hours in department A, Product 2 requires 1.50 hours in department A and Product 3 requires 3 hours in Department A. Thus, the constraint will be 2.00P1 + 1.50P2 + 3.00P3.
<span>If airlines are going to mine data from a captive audience several thousand feet in the air then they need to make a bigger deal of noting it. Much like the safety demonstration, before take off they should include a brief statement and have a Q & A sheet in the seat back. In this day and age protecting personal information is a touchy subject and not everyone is aware of that. You would think with the negative press for airlines these days and the huge debacles of cyber attacks and information leaks that airlines would be a bit more transparent on this practice.</span>
Answer:
Mark should invest:
- $30,000 in short term bonds
- $30,000 in intermediate term bonds
- $40,000 in long term bonds
Explanation:
S = short term bonds
I = intermediate term bonds
L = long term bonds
S + I + L = 100,000
0.04S + 0.06I + 0.07L = 0.058 x 100,000 = 5,800
S = I
2S + L = 100,000
L = 100,000 - 2S (now we replace both I and L)
0.04S + 0.06s + 0.07(100,000 - 2S) = 5,800
0.1S + 7,000 - 0.14S = 5,800
7,000 - 5,800 = 0.14S - 0.1S
1,200 = 0.04S
S = 1,200 / 0.04 = 30,000
I = 30,000
L = 100,000 - 60,000 = 40,000